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mafiozo [28]
3 years ago
14

What is cos theta when sin theta = sqrt 2/3

Mathematics
1 answer:
Fittoniya [83]3 years ago
3 0

<u>Answer:</u>

Value of cosθ is ±√7/3 .

<u>Step-by-step explanation:</u>

According to the Question , value of :

\red{\implies sin\theta = \dfrac{\sqrt2}{3}}

And , we know the identity of sine and cosine as ,

\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }

<u>Using</u><u> </u><u>,</u><u> </u><u>this</u><u> </u><u>ident</u><u>ity</u><u> </u><u>we</u><u> </u><u>have</u><u> </u><u>;</u><u> </u>

\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}

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