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vodomira [7]
3 years ago
11

Please help im stuck in a place where i do not wanna be

Mathematics
2 answers:
mylen [45]3 years ago
5 0

Answer:

Answers listed below

Step-by-step explanation:

1. (0,2)

2. (0,60)

3. (0,3)

4. (0,6)

5. (0,-4)

6. (0,3)

7. (0,-1)

8. (0,4)

9. (0,1)

10. (0,25)

Mark brainliest if this helped

Mark brainliest if this helped

Sever21 [200]3 years ago
4 0

Answer:

Hope this helps

Step-by-step explanation:

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A hungry elf ate 10 of your muffins. That was 5/8 of all of them! With how many did you start?
Tomtit [17]

The elf ate 5/8 of the 10 muffins you had to figure out how many were eaten,

1. you have to multiply 5/8 by 10

 5/8 · 10 = 6.25

2. now to figure out how many are left, subtract 6.25 from 10

10 - 6.25 = 3.75

8 0
3 years ago
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17. The perimeter P of a rectangle with length (
coldgirl [10]

Answer:

l= (P-2w)/2

Step-by-step explanation:

P = 2l + 2w

Subtractc 2w both sides

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Hope this helps!

4 0
4 years ago
If lies in the quadrant IV what can be the value of cos
Mrac [35]

When Ф lies in quadrant IV the value of cos Ф lies in [0, 1].

<h3>What is quadrant?</h3>

One fourth of the part of a circle is said to be the quadrant of the circle.

Given the angle Ф lies in quadrant IV.

As we know, cos Ф is positive only in first and fourth quadrant i.e when Ф lies in 0<Ф<90 and 270<Ф<360.

cosФ range from [-1,1]

So, cos Ф is positive when Ф lies in 1st and 4th quadrant.

&  cos Ф is negative when Ф lies in 2nd and 3rd quadrant.

If cos ∅ lies in the quadrant IV, anything between [0, 1] can be the value of cos ∅.

Hence, when Ф lies in quadrant IV the value of cos Ф lies in [0, 1].

Learn more about quadrant.

brainly.com/question/7196312

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5 0
3 years ago
The sum of two numbers is 84. The first is 8 less than 3 times the other.
poizon [28]

Answer:

25.3 and

Step-by-step explanation:

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3 years ago
(3 + 4i) - (8 -5i) Write answer in standard form a +bi Group of answer choices
Anton [14]

Answer:

A=-5+9i

Step-by-step explanation:

\left(3+4i\right)-\left(8-5i\right)\\\\\mathrm{Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number}\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\\\=\left(3-8\right)+\left(4+5\right)i\\3-8=-5\\4+5=9\\\\=-5+9i

5 0
3 years ago
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