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3 years ago

8,17,26,... Find the 31st term.

Mathematics

2 answers:

Neko [114]3 years ago

8 0

Answer:

a1 =a1+(n-1) *d =8+(1-1)*9=8

a2 =a2+(n-1) *d =8+(2-1)*9=17

a3 = a3+(n-1) *d =8+(3-1)*9=26

Sana po makatulong :)

GarryVolchara [31]3 years ago

8 0

Answer:

The answer is 278.

Step-by-step explanation:

https://www.tiger-algebra.com/drill/8,17,26,35,44,53,62,71/

a31 =a1+(n-1)*d =8+(31-1)*9 =278

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The 20 to 34 age groups are approximately normally distributed with µ = 110

Savatey [412]

Answer:

21.94% of people aged 20 to 34 have IQs between 125 and 150.

Step-by-step explanation:

The complete question is: Scores on the Wechsler Adult Intelligence Scale (a standard IQ test) for the 20 to 34 age group are approximately Normally distributed with μ = 110 and σ = 25.

What percent of people aged 20 to 34 have IQs between 125 and 150?

Let X = Scores on the standard IQ test for the 20 to 34 age group

SO, X ~ Normal( $\mu=110,\sigma^{2} =25^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 110

$\sigma$ = standard deviation = 25

Now, the percent of people aged 20 to 34 have IQs between 125 and 150 is given by = P(125 < X < 150) = P(X < 150) - P(X $\leq$ 125)

P(X < 150) = P( $\frac{X-\mu}{\sigma}$ < $\frac{150-110}{25}$ ) = P(Z < 1.60) = 0.9452

P(X $\leq$ 125) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{125-110}{25}$ ) = P(Z $\leq$ 0.60) = 0.7258

The above probability is calculated by looking at the value of x = 1.60 and x = 0.60 which has an area of 0.9452 and 0.7258.

Therefore, P(125 < X < 150) = 0.9452 - 0.7258 = 0.2194 or 21.94%

7 0

3 years ago

If a is directly proportional to b, and a = 25 when b = 35, find b when a = 40

koban [17]

If a is directly proportional to b, we have the relationship to be:

$\begin{gathered} a\propto b \\ \therefore \\ a=kb \\ where \\ b=constant \end{gathered}$

When a = 25, b = 35. Therefore, we can calculate the value of k as follows:

$\begin{gathered} 25=35k \\ k=\frac{25}{35} \\ k=\frac{5}{7} \end{gathered}$

Therefore, the relationship is given to be:

$a=\frac{5}{7}b$

When a = 40, we can calculate the value of b to be:

$\begin{gathered} 40=\frac{5}{7}b \\ 40\times7=5b \\ 5b=280 \\ b=\frac{280}{5} \\ b=56 \end{gathered}$

The value of b is 56.

7 0

1 year ago

Consider the graph of the function f(x) = 2(x + 3)2 + 2. Over which interval is the graph decreasing? (–∞, –3) (–∞, 2) (–3, ∞) (

SOVA2 [1]

Answer:

(–∞, –3)

Step-by-step explanation:

The function $f(x) = 2(x + 3) ^ 2 +2$ is a quadratic function of order 2 and positive coefficient.

This is in the form of the function $y = x^2$ , but it is displaced 3 units to the left of the x axis and two units up in the y axis. type of functions are decreasing from -∞ to its vertex and then they are increasing from the vertex to infinity.

Observe in the attached graph that this function has its vertex in the point (-3, 2) and is decreasing from -∞ to x = -3. Then it is increasing until ∞. Therefore the correct option is:

(-∞, -3)