Answer:
10.50°C
Step-by-step explanation:
Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3
The rate of change in temperature of the bug path can be expressed using the composite formula:
dT/dt = Tx(dx/dt) + Ty(dy/dt)
If x = 2+t; dx/dt = 1
If y = 1+12t; dy/dt = 1/2
Substituting the parameters gotten into dT/dt we will have;
dT/dt = 9(1)+3(1/2)
dT/dt = 9+1.5
dT/dt = 10.50°C/s
Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s
1st) 275+70-50 Lastly: Subtract -350 - 295 = - 55
275+70 = 345 The answer is - 55
345 - 50 = 295
Answer:
I´m pretty sure it´s 2.(-3,6).
Step-by-step explanation:
60 because
4^2 + 9*4 + 8
16+36+8
60
hope this helps!
