Answer:
what I dont even know whT your talking about. could you please explain your question a bit more?? then maybe I could help you out
Slope intercept form is y=MX+b.
M is the slope, x is the x intercept, and b is the y intercept
the slope is
An intercept is where the formula crosses the axis. therefore, the x intercept is .5, and the y intercept is 1
so the point slope formula is
B. (6, -8)
First, you need to figure out the slope of the line
(y1 - y2) / (x1 - x2)
After substituting points D(-3, 4) A(3, -4)
[4 - (-4)] / (-3 - 3)
(8) / (-6)
The slope of the line is -8/6 or -4/3 simplified
Then you can put it in point slope form:
(y - y1) = m(x - x1)
(y - y1) = -4/3(x - x1)
The point that I am using for point slope form is A(3, -4)
[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)
Next you have to simplify the equation so that y is isolated
y + 4 = -4/3(x - 3)
First distribute the -4/3
y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4
Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x
Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal
For example) (6, -8)
-8 = -4/3(6)
-8 = -8
So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D
~~hope this helps~~
Answer:
Step-by-step explanation:
![x_{1}=7 \ ; y_{1} = -4\\\\x_{2} = -8 \ ; y_{2}=5\\\\CD = \sqrt{(-8-7)^{2}+(5-[-4])^{2}}\\\\=\sqrt{(-15)^{2}+(5+4)^{2}}\\\\=\sqrt{225+(9)^{2}}\\\\=\sqrt{225+81}\\\\=\sqrt{306}\\\\=\sqrt{3*3*2*17}\\\\=3\sqrt{34}](https://tex.z-dn.net/?f=x_%7B1%7D%3D7%20%5C%20%3B%20y_%7B1%7D%20%3D%20-4%5C%5C%5C%5Cx_%7B2%7D%20%3D%20-8%20%5C%20%3B%20y_%7B2%7D%3D5%5C%5C%5C%5CCD%20%3D%20%5Csqrt%7B%28-8-7%29%5E%7B2%7D%2B%285-%5B-4%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%28-15%29%5E%7B2%7D%2B%285%2B4%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B225%2B%289%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B225%2B81%7D%5C%5C%5C%5C%3D%5Csqrt%7B306%7D%5C%5C%5C%5C%3D%5Csqrt%7B3%2A3%2A2%2A17%7D%5C%5C%5C%5C%3D3%5Csqrt%7B34%7D)
Distance = 
