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dsp73
3 years ago
11

6y - 26 and 2(3 - 13) Are they equivalent?

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0

Answer:

٢٤٦ ٤٧ ٥١٩+٣٦

Step-by-step explanation:

)اتييمثتنث)٢-ثعه1غميصك

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If k is a positive integer and n = k(k + 7), is n divisible by 6 ? (1) k is odd. (2) When k is divided by 3, the remainder is 2.
olganol [36]

Answer:

1.) Yes

2.) Yes

Step-by-step explanation:

Given that

n = k(k + 7)

If k is a positive integer and n = k(k + 7), is n divisible by 6 ?

(1) k is odd. Yes.

Let assume that k = 3

Then, n = 3(3 + 7)

n = 3 × 10

n = 30.

30 is divisible by 6.

(2) When k is divided by 3, the remainder is 2. That is,

Let k = 5

Then,

5/3 = 1 remainder 2

Substitute k into the equation

n = k(k + 7)

n = 5(5 + 7)

n = 5 × 12

n = 60

And 60 is divisible by 6.

Therefore, the answer to both questions is Yes.

5 0
3 years ago
20.   The sum of two consecutive even integers is 158. Find the least of the two integers. 
Mumz [18]

Answer:

78

Step-by-step explanation:

The tricky part of this is figuring out how to assign the unknowns.  We are told that we are working with two consecutive even integers.  Consecutive means "next to" or "in order" and sum means to add.  If we use 2 and 4 as examples of our 2 consecutive even integers and assign x to 2, then in order to get from 2 to 4 we have to add 2.  So the lesser of the 2 integers is x, and the next one in order will be x + 2.  (2 and 4 are just used as examples; they mean nothing to the solving of this particular problem.  You could pick any 2 even consecutive integers and find the same rule applies.  All we are doing here with the example numbers is finding a rule for our integers.)  Now we have the 2 expressions for the integers, we will add them together and set the sum equal to 158:

x + (x + 2) = 158

The parenthesis are unnecessary since we are adding, so when we combine like terms we get

2x + 2 = 158 and

2x = 156 and

x = 78

That means that the lesser of the 2 integers in 78, and the next one in order would be 80, and 78 + 80 = 158

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