6300kg = 6300000g 6300000g = 6.3 x 10^6
Answer:
<h2>m∠EFG = 126°</h2><h2>m∠GFH = 54°</h2>
Step-by-step explanation:
If ∠EFG and ∠GFH are a linear pair, then m∠EFG + m∠GFH = 180°
(look at the picture).
We have
m∠EFG = 5n + 16
m∠GFH = 2n + 10
Substitute:
(5n + 16) + (2n + 10) = 180 <em>combine like terms</em>
(5n + 2n) + (16 + 10) = 180
7n + 26 = 180 <em>subtract 26 from both sides</em>
7n + 26 - 26 = 180 - 26
7n = 154 <em>divide both sides by 7</em>
7n/7 = 154/7
n = 22
Insert the value of n into expressions that specify angle measures:
m∠EFG = 5n + 16 → m∠EFG = 5(22) + 16 = 110 + 16 = 126°
m∠GFH = 2n + 10 → m∠GFH = 2(22) + 10 = 44 + 10 = 54°
Answer:
2 hours
Step-by-step explanation:
The question is asking us to get the meeting point of the two and at what time would they arrive here given their individual speeds. Now what needs to be done here is first add their average speeds.
The total average speed = 325 + 25 = 350km/h
Now the distance the helicopter would have traveled would be ; 325/350 * 700 = 650km
The remaining distance left for the boat would be 700 - 650 = 50km
Now the time taken for this would be 650/325 or 50/25 = 2hours
Answer:
T=12/7 For mixed number T=1 5/7 for decimal form 1.7 (7 repeating)
Answer:
52
Step-by-step explanation:
Using the Pythagorean theorem
a^2+b^2 = c^2
20^2 + 48^2 = c^2
400 +2304=c^2
2704=c^2
Taking the square root of each side
sqrt(2704) = sqrt(c^2)
52 = c