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3 years ago

Answer fast please! I need an answer before 9:00!

Mathematics

2 answers:

dolphi86 [110]3 years ago

4 0

Answer:

1536 cm^2 be the correct answ

Usimov [2.4K]3 years ago

3 0

Answer: Option 2

1536cm²

Lateral Area=32×(24/2)×4

=1536 (cm²)

Answered by Gauthmath must click thanks and mark brainliest

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5. Mrs.Weed's puppy weighed o.236 kg when it was born. At the next check-up it weighed 0.37 kg. How much weight had it gained?

musickatia [10]

Answer:

5.) 0.134 kg.

6.) 6.15 km.

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Step-by-step explanation:

5.) 0.37 - 0.236 = 0.134

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2 years ago

What is the x-coordinate of the solution of the system? x+y+3 4x-y=-38

steposvetlana [31]

Note: I am assuming the first equation is:

x+y = 3

Answer:

The solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

Step-by-step explanation:

Given the system of equations

$\begin{bmatrix}x+y=34\\ x-y=-38\end{bmatrix}$

subtracting the equations

$x-y=-38$

$-$

$\underline{x+y=34}$

$-2y=-72$

solve -2y for y

$-2y=-72$

Divide both sides by -2

$\frac{-2y}{-2}=\frac{-72}{-2}$

$y=36$

For x+y=34 plug in y = 36

$x+36=34$

Subtract 36 from both sides

$x+36-36=34-36$

Simplify

$x=-2$

Thus, the solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

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2 years ago

Which expression is equivalent to (XY^−6)^2 XY^−36 x^2y^−12 x ^2y^12 xy^36

Margaret [11]

Answer:

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Step-by-step explanation:

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3 years ago

The area of a rectangle is 504 square meters. If the perimeter is 90 meters, find the length and width of the rectangle.

o-na [289]

Answer:

Length =24m and width = 21m

Step-by-step explanation:

Given,

Area of rectangle, A = 504 m^2

Perimeter of rectangle, P = 90 m

Since we know, A = Length * width and P = 2(Length + width)

So, A = L * w

=> 504 = L*w ------------------(1)

And P = 2(L + w)

=> 90 =2( L + w) ----------------(2)

Plug L =504/w in equation 2

i.e. 90 = 2( 504/w + w)

or 45 = 504/w + w

or 45 = (504 + w^2 ) / w

or 45w = 504 + w^2

or w^2 - 45w + 504 = 0

On solving above quadratic equation we get:

w = 21 or 24

So we take width , w= 21 meter

Then length will be, L =504/21 =24 meter

Hence length and width of rectangle are 24m and 21m respectively.

5 0

3 years ago