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topjm [15]
4 years ago
14

At the top of a building you and a friend throw two identical baseballs exactly horizontal away from the building releasing the

ball at exactly the same time. Your friend throws the baseball twice as fast as you.
a)friends ball hits the ground after yours but goes twice as far
b) your friends ball hits the ground after yours and goes 1.5 as far
c) your friends ball hits the ground at the same time as yours, and goes twice as far d)your friends ball hits the ground at the same time as yours and goes twice the distance
Physics
1 answer:
just olya [345]4 years ago
8 0

Answer:

Option C

your friends ball hits the ground at the same time as yours, and goes twice as far

Explanation:

The vertical speed is the same but the horizontal speed of your friend is twice yours. This implies the time to hit the ground is the same but after hitting the ground since the horizontal speed of your friend is twice, then the ball moves a horizontal diatance twice yours. Therefore, option C is correct.

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Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has
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Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

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Explanation:

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East component: 3.9 m/s

South component: 1.8 m/s

Explanation:

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brainly.com/question/2678571

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