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Nataly [62]
4 years ago
12

Which of the following tools is used to mark the spot where a hole is to be drilled in a piece of metal?

Physics
2 answers:
Oxana [17]4 years ago
3 0
That's a job for a center-punch.
Snowcat [4.5K]4 years ago
3 0

Answer: Option (b) is the correct answer.

Explanation:

Center punch is a tool which helps to mark a point where we intend to punch a hole in the material without slipping in any direction.

With the help of this mark, it provides a resting place to the drill so that while drilling the hole will be pointed in the right direction.

Thus, we can conclude that out of the given options center punch is the tool used to mark the spot where a hole is to be drilled in a piece of metal.  




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A boat takes off from a dock at 2.5 m/s and speeds up at 4.2 m/s squared for six seconds how far has the most traveled
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x=\left(2.5\,\dfrac{\mathrm m}{\mathrm s}\right)(6\,\mathrm s)+\dfrac12\left(4.2\,\dfrac{\mathrm m}{\mathrm s^2}\right)(6\,\mathrm s)^2

\implies x=91\,\mathrm m

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A block with mass m1 = 4.50 kg and a ball with mass m2 = 7.70 kg are connected by a light string that passes over a frictionless
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How are mathematics and science related?
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Which of the following devices is associated with the reception of radio signals?
ki77a [65]
What are the "following" devices ? ?
I think they're a list of choices that you have but aren't sharing.

A few devices associated with the reception of various types of
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6 0
3 years ago
Read 2 more answers
A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica
-BARSIC- [3]

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

7 0
3 years ago
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