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3 years ago

What can you do to realign your biological clock with the external world when you work a rotating shift?

1 answer:

wel3 years ago

6 0

The "biological clock" of an organism is referred to as the circadian rhythm and it s a 24 hour cycle of the physiological processes taking place in that organism. This cycle affects the breathing and eating patterns of people, and is affected by external cues such as temperature and sunlight. Therefore, if someone's circadian rhythm is disrupted due to working rotating shifts or because of traveling, then it may be reset by exposure to bright sunlight while working.

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A series RL circuit includes a 6.05 V 6.05 V battery, a resistance of R = 0.655 Ω , R=0.655 Ω, and an inductance of L = 2.55 H.

Ivenika [448]

Answer:

The induced emf 1.43 s after the circuit is closed is 4.19 V

Explanation:

The current equation in LR circuit is :

$I=\frac{V}{R} (1-e^{\frac{-Rt}{L} })$ .....(1)

Here I is current, V is source voltage, R is resistance, L is inductance and t is time.

The induced emf is determine by the equation :

$V_{e}=L\frac{dI}{dt}$

Differentiating equation (1) with respect to time and put in above equation.

$V_{e}= L\times\frac{V}{R}\times\frac{R}{L}e^{\frac{-Rt}{L} }$

$V_{e}=Ve^{\frac{-Rt}{L} }$

Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.

$V_{e}=6.05e^{\frac{-0.655\times1.43}{2.55} }$

$V_{e}=4.19\ V$

5 0

3 years ago

What is the the acceleration of a proton that is 4.0 cm from the center of the bead? input positive value if the acceleration is

QveST [7]

Missing detail in the text:
"<span>A small glass bead has been charged to + 25 nC "

Solution
The force exerted on a charge q by an electric field E is given by
</span> $F=qE$
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span> $E=k_e \frac{Q}{r^2}$
with $k_e = 8.99\cdot 10^9 Nm^2/C^2$ , $Q=+25 nC=25 \cdot 10^{-9}C$ is the charge on the bead. We want to calculate the field at $r=4.0 cm=0.04 m$ :
$E=(8.99\cdot 10^9) \frac{25\cdot 10^{-9}}{(0.04)^2}=1.4\cdot 10^5 V/m$
The proton has a charge of $q=1.6\cdot 10^{-19}C$ , therefore the force exerted on it is
$F=qE=1.6\cdot 10^{-19}C \cdot 1.4\cdot 10^5 V/m=2.25\cdot 10^{-14} N$

And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass, $m=1.67\cdot 10^{-27} kg$ , we have
$F=ma$
$a= \frac{F}{m}= \frac{2.25\cdot 10^{-14} N}{1.67\cdot 10^{-27} kg}=1.35 \cdot 10^{13} m/s^2$

The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
$a=-1.35 \cdot 10^{13} m/s^2$

6 0

4 years ago

What is thermodynamics

icang [17]

Answer:

The science of the conversions between heat and other forms of energy.

Explanation:

5 0

3 years ago

Read 2 more answers

22. On a day the wind is blowing toward the south at 3m/s, a runner jogs west at 4m/s. What is the velocity of the air relative

blagie [28]

The velocity of the air relative to the runner is 5 m/s.

<h3>What is the relative velocity?</h3>

We must recall that velocity is a vector quantity and the relative velocity must be obtained vectorially. Thus we know that;

Velocity of the runner = 4m/s. due west

Velocity of the wind = 3m/s due south

The relative velocity is;

Vr = √(4)^2 + (3)^2

Vr = 5 m/s

Learn more about relative velocity:brainly.com/question/20813206

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3 0

2 years ago

Q.1- A 3000 cm3 tank contain O2 gas at 20 °C and a gauge pressure of 2.5 x 106 Pa. Find the mass of oxygen in the tank.

exis [7]

20c because te mass of the object is larger than the table

3 0

3 years ago