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professor190 [17]
3 years ago
12

Assume the equation has a solution for z. -cz+ 6z = tz + 83z=?​

Mathematics
1 answer:
solong [7]3 years ago
5 0

Answer:

z = 83 / (- c + 6 - t)

Step-by-step explanation:

Given:

-cz+ 6z = tz + 83

z=?​

-cz+ 6z = tz + 83

Collect like terms

-cz+ 6z - tz = 83

Factorize

z(- c + 6 - t) = 83

Divide both sides by (- c + 6 - t)

z(- c + 6 - t) / (- c + 6 - t) = 83 / (- c + 6 - t)

z = 83 / (- c + 6 - t)

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Answer:

Tina won 5 games more than maryann, and the sum of their games is 29.. 29-5/2= 12

Maryann won 12 games while Tina won 12+5= 17 games.

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3 years ago
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Which of the following is not a true statement about pi?
FinnZ [79.3K]

Answer:

Option D.The ratio of the radius of a circle to its circumference

Step-by-step explanation:

<em>Verify each statement</em>

A) The ratio of the circumference of a circle to its diameter

The statement is True

Because

C=\pi D

so

\pi=C/D

B) Approximated to be 3.14

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D) The ratio of the radius of a circle to its circumference

The statement is not True

Because

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3 years ago
Rapper DaBaby drove at a speed of 45 mph in front of Coosa High School on his way home from North Carolina. What was his speed i
NeTakaya
To find the answer, set up an equation:
\frac{45 \: miles}{1 \: hour}  \times  \frac{1000 \: meters}{1 \: mile}  \times  \frac{1 \: hour}{3600 \: seconds}  =
Using this set up we can cross out the units that are on opposite sides of the proportion such as miles and hours, leaving us with the desired units of meters and seconds. Then calculate m/s by multiplying 45 by 1000 meters and then dividing that value by 3600 seconds.

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Step-by-step explanation:

Hey there!!

You can simply use midpoint formulae to find midpoint of the coordinates.

Here, Given that;

G(3,3) and H(-7,7).

Using midpoint formulae,

midpoint \: of \: gh =  (\frac{x1 + x2}{2}  ,\frac{y1 + y2}{2})

midpoint \: of \: gh =  (\frac{3 - 7}{2}  ,\frac{3 + 7}{2})

After simplifying it we get,

= (-2,5).

Therefore, midpoint of GH is M(-2,5).

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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