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3 years ago

Need help on geometry 2

Mathematics

1 answer:

bekas [8.4K]3 years ago

8 0

$x=4$

$h=4\sqrt{3}$

Area= $32\sqrt{3}$ (answer A)

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Lea is making a mosaic picture that is 3/4 foot tall and 11/12 foot wide what is the area of her mosaic

Fudgin [204]

Not enough info. But assuming it’s a rectangular, area = length * width
3/4*11/12 = 33/48 = 11/16 square feet

4 0

3 years ago

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

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3 years ago

Solve 4x^2 - 36x + 32 = 0<br><br>Sorry! It's suppose to be + 32.<br>Please show all work.

mylen [45]

Answer:

x=1, x=8

Step-by-step explanation:

4x2−36x+32=0

Step 1: Factor left side of equation.

4(x−1)(x−8)=0

Step 2: Set factors equal to 0.

x−1=0 or x−8=0

(+1) (+8)

x=1 or x=8

6 0

3 years ago

Eva is a kickboxing instructor who will be teaching classes at a local gym. To get certified as an instructor, she spent a total

zlopas [31]

Answer:57+51+3

Step-by-step explanation: use https://www.cymath.com/

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3 years ago

The numbers in this sequence increase by the same amount each time.

PilotLPTM [1.2K]

Answer:

2, 4, 6, 8 , 10

Step-by-step explanation:

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3 years ago