3 years ago

Prove that 1-tan32°tan13°-tan32°-tan13°=0

Mathematics

1 answer:

Step2247 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

45=32+13

tan 45=tan(32+13)

$1=\frac{tan~ 32+tan~ 13}{1-tan ~32 ~tan~ 13} \\cross~multiply \\1-tan 32 ~tan~13=tan ~32+tan~13\\$

or 1-tan 32 tan 13-tan 32-tan 13=0

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Prove that 1-tan32°tan13°-tan32°-tan13°=0​

Prove that 1-tan32°tan13°-tan32°-tan13°=0