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3 years ago

Prove that 1-tan32°tan13°-tan32°-tan13°=0

Mathematics

1 answer:

Step2247 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

45=32+13

tan 45=tan(32+13)

$1=\frac{tan~ 32+tan~ 13}{1-tan ~32 ~tan~ 13} \\cross~multiply \\1-tan 32 ~tan~13=tan ~32+tan~13\\$

or 1-tan 32 tan 13-tan 32-tan 13=0

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Use the percent bar model to find the missing percent

Ne4ueva [31]

A percentage is a way to describe a part of a whole. The missing percent on the bar model is equal to 12.5%.

<h3>What are Percentages?</h3>

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

On the percent bar model, above the missing percentage, the fraction is given as 1/8.

Now, the given fraction 1/8 in the form of percentage can be written as,

1/8

= 1/8 × 100%

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Hence, the missing percent on the bar model is equal to 12.5%.

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2 years ago

Which diagram shows parallel lines cut by a transversal? 2 lines are cut by a transversal. At the intersection of the first line

AlekseyPX

Answer:

Step-by-step explanation:

2 lines are cut by a transversal. At the intersection of the first line with the transversal, the bottom right angle is 130 degrees. At the intersection of the second line with the transversal, the uppercase right angle is 50 degrees.

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3 years ago

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Henry buys a large boat for the summer, however he cannot pay the full amount of $32,000 at

Anna007 [38]

Answer:

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

Step-by-step explanation:

Loan payment per month=Amount to pay÷discount factor

Mathematically P=A÷D

where D is the discount factor calculated using the formula;

$\frac{(1+i)^n-1}{i(1+i)^n}$

where i=periodic interest rate=annual rate divided by number of payment periods

A is the amount to pay after downpayment

P is the loan monthly payment amount

n=number of periodic payments=payments per year times number of years

⇒In this question you find the discount factor then divide the amount remaining to pay with the discount factor to get monthly payments

Given;

Cost of boat=$32000

Down payment=$14000

Loan to pay=$32000-$14000=$18000

Annual rate=5.5%=i=5.5%÷12=0.458%⇒0.00458

Periodic payments, n=4×12=48

Finding the discount factor D;

$D=\frac{(1+i)^n-1}{i(1+i)^n} \\\\\\D=\frac{(1+0.00458)^{48} -1}{0.00458(1+0.00458)^{48} } \\\\\\D=\frac{1.2455-1}{0.005703} \\\\\\D=\frac{0.2455}{0.005703} =43.05$

To get the amount to pay monthly divide the loan to pay with the discount factor

$=\frac{18000}{43.05} =418.14$

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

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3 years ago

A group of 52 people attend a ball game. There were three times as many men as women in the group. Write and solve a system of e

kkurt [141]

Answer:

lets call the children, c, and call adult, a,

c+a= 52 eq 1: a=52-c

c=3a eq 2

take a's value from eq 1 and plug it into eq 2

c=3(52-c)

c=156-3c

4c=156

c=39 the number of children that attended the ball game.

Step-by-step explanation:

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3 years ago

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Nina decided to raise money for a community organization that provides free classes and legal

Over [174]

A percentage is a way to describe a part of a whole. The money that is raised by Nina in the second month is $960.

<h3>What are Percentages?</h3>

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

Given that the money raised by Nina in the first month is $800, while the money raised by Nina in the second month is 20% more.

Therefore, the money raised by Nina in the second month is,

Money raised = $800 + 20% of $800

= $800 + 0.20($800)

= $800 + $160

= $960

Hence, the money that is raised by Nina in the second month is $960.

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2 years ago

Prove that 1-tan32°tan13°-tan32°-tan13°=0​

Prove that 1-tan32°tan13°-tan32°-tan13°=0