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pogonyaev
2 years ago
12

5. Why are the noble gases such as helium (He) and neon (Ne) grouped

Chemistry
1 answer:
GalinKa [24]2 years ago
8 0

Answer:

A. They are nonreactive gases

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If an atom contains one electron and one proton,will it carry any charge or not​
sertanlavr [38]

Answer:

no it will have no charge...it would be electrically neutral! because the number of protons and electrons are equal!

8 0
3 years ago
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What is the only true way to tell if a chemical reaction has occurred?<br> CFU
Murljashka [212]

Answer:

change of colour

Explanation:

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3 years ago
Changing the pendulum design after the first trial was an example of _____________ to solve the problem presented by the teacher
Luden [163]

Answer:

Changing the pendulum design after the first trial was an example of <u>evaluating the model</u> to solve the problem presented by the teacher.

Explanation:

A model constitutes an abstract representation of a certain aspect of reality, and has a structure that is formed by the elements that characterize the aspect of the modeled reality and by the relationships between these elements.

This achieved result provides a better understanding of the problem being studied, offering aspects that can be changed or improved to solve the problem posed, obtaining more information about the reality of the phenomenon that is being represented.

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3 years ago
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At 25°c the henry's law constant for nitrogen trifluoride (nf3) gas in water is 7.9 × 10-4 m/atm. what is the mass of nf3 gas th
Step2247 [10]
For this problem, we should use the Henry's Law formula which is written below:

P = kC
where
P is the partial pressure of the gas
k is the Henry's Law constant at a certain temperature
C is the concentration

Substituting the values,
1.71 atm = (7.9×10⁻⁴<span> /atm)C
Solving for C,
C = 2164.56 molal or 2164.56 mol/kgwater

Let's make use of density of water (</span>1 kg/1 m³) and the molar mass of NF₃ (71 g/mol).<span>

Mass of NF</span>₃ = 2164.56 mol/kg water * 1 kg/1 m³ * 1 m³/1000000 mL * 150 mL * 71 g/mol = 23.05 g 
4 0
3 years ago
Lance is a 60-kg runner who, on a good day, runs at a speed of 5 m/s. What is his kinetic energy when he runs at this speed? *
Contact [7]

Answer:

His kinetic energy when he runs at that 5 m/s is 750 joules

Explanation:

The given information are;

The mass of, Lance, the runner = 60-kg

The speed by which Lance is running = 5 m/s

The kinetic energy, KE, is given by the relation;

KE = 1/2×m×v²

Where;

m = The mass = 60-kg

v = The instantaneous speed of motion = 5 m/s

The kinetic energy can be found by substituting the values of the variables in the kinetic energy equation as follows;

KE = 1/2 × 60 kg × (5 m/s)² = 750 joules

His kinetic energy when he runs at that 5 m/s is 750 joules.

7 0
3 years ago
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