Answer:
Explanation:
70% (vol/vol) means
cotnaimns 70 %(vol/vol) 70 ml of isoprapnol is there in 100 ml of Rubbing sold alcohol.
if it is 200 ml then obvouly it has the 70*2 =140 ml of isoproanol required.
Answer: 30.06% is your answer.
I hope this helps.
Stay safe and have a good day :D
Explanation:
Since 10mm is 1cm
<em>There</em><em>fore</em><em> </em><em>7</em><em>.</em><em>6</em><em>0</em><em>c</em><em>m</em><em> </em><em>is</em><em> </em><em>7</em><em>6</em><em>0</em><em>m</em><em>m</em>
<em>Since</em><em> </em><em>1</em><em> </em><em>inch</em><em> </em><em>is</em><em> </em><em>2</em><em>.</em><em>5</em><em>4</em><em>c</em><em>m</em>
<em>There</em><em>fore</em><em> </em><em>7</em><em>.</em><em>6</em><em>0</em><em>c</em><em>m</em><em> </em><em>is</em><em> </em><em>3</em><em>.</em><em>1</em><em>0</em><em> </em><em>inches</em>
Answer:
b. 3.66x10²³ atoms of chromium.
Explanation:
First we calculate how many moles are there in 31 grams of chromium, using its molar mass:
- Molar Mass of Chromium = 51 g/mol (This can be found on any periodic table)
- 31 g ÷ 51 g/mol = 0.608 mol
Then we <u>calculate how many atoms are there in 0.608 moles</u>, using <em>Avogadro's number</em>:
- 0.608 mol * 6.023x10²³ atoms/mol = 3.66x10²³ atoms
The correct answer is thus option b. 3.66x10²³ atoms of chromium.
