Answer:
The process of making S'more by adding chocolate bar, gram-crackers, and marshmallows in layers is not a chemical reaction
Explanation:
In a chemical reaction, the substances involved in the reaction are known as the reactants and the substances produced have different physical and chemical properties than those of the reactants and they are known as the products.
The bonds that hold the atoms of the reactants are broken down and rearranged, creating entirely new substances as products. Therefore, energy must be added and/or evolved in any chemical reaction and all reactant atoms should be involved in the reaction.
The change in energy can be sensed as heat change such as increase or decrease in the temperature of the products
Since S'more does not involve any of the above changes that occur in a chemical reaction when the chocolate bar, gram-crackers, and marshmallows are put together, it is not a chemical change or a chemical reaction.
The conclusion was that there must be space between the particles of an atom. The way he knew this is because while some of the radiation reflected off of the gold foil, other radiation went right through it.
Answer is 6 Na + (aq) +3 CA swaured + 6 CI- (aq)
Answer:
B. oxidation; reduction
Explanation:
A voltaic cell is electro-chemical cell in which chemical energy is converted into electrical energy.
1. This cell utilizes chemical reaction to generate electric.\
2. there two electrode anode and cathode
3. At Anode oxidation occurs
4. At cathode reduction occurs
5. chemical is present in the cell which is electrolyte which completes the circuit of the voltaic cell.
- oxidation is the process in which there is loss of electrons
- Reduction is the process in which there is gain of electrons
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Based on above discussion
At anode oxidation takes place
At cathode reduction takes place.
Hence, correct option is B. oxidation; reduction
Solution :
For the reaction :
we have
![$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$](https://tex.z-dn.net/?f=%24Ka%20%3D%20%5Cfrac%7B%5B%5Ctext%7BTris%7D%5E-%20%5Ctimes%20H_3O%5D%7D%7B%5Ctext%7BTris%7D%5E%2B%7D%24)
Clearing 
, we have 
So to reach 
, one must have the 
concentration of the :
![$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$](https://tex.z-dn.net/?f=%24%5Ctext%7B%5BOH%7D%5E-%5D%3D10%5E%7B-pOH%7D%20%3D%206.31%20%5Ctimes%2010%5E%7B-7%7D%20%5Ctext%7B%20moles%20of%20base%7D%24)
So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.
Volume NaOH 
Tris mass 
Now to prepare the said solution we must mix:
gauge to 1000 mL with water.
