Simplify <br><br> √250x^16 / √2x

The daytime high temperature on the moon can reach 130°C. The nighttime low temperature can get as low as −110°C. What is the di

maks197457 [2]

Answer:

240

Step-by-step explanation:

remember that to get from positive to negative you have to go from positive to 0 then to negative .

however the easiest way of solving this is

add both the values , ignore the sign

130 + 110

the difference in the temperature is :

= 240 degrees

7 0

3 years ago

Here is the histogram of a data distribution. All class widths are 1.

Lera25 [3.4K]

It’s C. Since that’s the middle based on the diagram

6 0

2 years ago

Px + qy = r<br> 2px - qy = 2r<br> When solving this system of equations, x =

VladimirAG [237]

Px + qy = r
2px - qy = 2r
----------------add
3px = 3r

x = 3r/3p
x = r/p

8 0

3 years ago

Read 2 more answers

Please help.. part a & b

umka21 [38]

Answer:

Part A

to the 10th power will be positive and to the 11th power is negative. When the exponent is even it will be positive. When it is odd it will be negative

Part B

The one with the negative enclosed will be positive. The second one, the exponent is only effecting the number and not the sign. The outcome will always be negative.

4 0

3 years ago

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0

3 years ago

Simplify √250x^16 / √2x