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lyudmila [28]
3 years ago
13

Geo weighed five boxes before you ship them the way it's worth 50 to 48 4854 and 50 which statement is true the median in the mo

tor equal the mold is equal to the minimum the mold is greater than mean that means less than the median median
Mathematics
1 answer:
NISA [10]3 years ago
3 0

Answer:

a

Step-by-step explanation:

Here is the question used in answering this question :

Gio weighed five boxes before he shipped them. The weights were: 52,48,48,54, and 50. Which statement is true?

A) The mode is equal to the minimum

B)  The mode is greater than the mean

C)  The median and mode are equal

D) The mean is less than the medium

Mode is the number that occurs the most. that number is 48.

Mean = sum of numbers / n = 52 + 48 + 48 + 54 + 50  / 5 = 50.4

Median is the middle number

Arranging the numbers in ascending order : 48, 48. 50, 52, 54. The median is 50

the mode is 48 which is equal to the minimum

the mean is greater than the mode

the mode and median are different figures

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Answer:

g+3 +36+8=

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Step-by-step explanation:

4 0
3 years ago
Given that f(x)=x2−4 and g(x)=x+3 , what are all the values of x for which f(g(x))=0 ?
d1i1m1o1n [39]

Answer:

the answer is (x )

math  way  helps

Step-by-step explanation:

5 0
2 years ago
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
3 years ago
Cashews cost $4 per pound and peanuts cost $2.50 per pound. If you mix 4 pounds of cashews and 4 pounds of peanuts, what is the
SCORPION-xisa [38]

$6.50 per pound $4.00 +$2.50=$6.50

6 0
4 years ago
Anyone, please help me!!!​
lianna [129]

Answer:

Step-by-step explanation:

Hint:  1- 2sin²x = Cos 2x

LHS = 1 - 2Sin² (π/4 - Ф/2)

        =  Cos 2 *(π/4 - Ф/2)

        = Cos 2*π/4 - 2*Ф/2

         = Cos π/2 - Ф

         = Sin Ф =  RHS

7 0
3 years ago
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