Given:$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633
= # of adults attended700-633
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= c =
66
= # of children attended
Step-by-step explanation:
- 3x+5y=7b equation 1
- 2x+4y=1
2x=-4y+1
- x=(-4y+1)/2
- x=(-4y+1)/2 in equation 1
3×(-4y+1)/2+5y=7b
(-12y+3)/2+5y=7b
(-12y+3+10y)/2=7b
(-12y+3)/2=7b
-12y+3=14b
-12y=14b-3
- y=3-14b/12
- y=3-14b/12 in x=(-4y+1)/2
x=(-4×{3-14b/12}+1)/2
x=(-3+14b)/3+1/2
x=14b/3×1/2
Example of integers are -5 ,1 ,5 , 8 , 97 and 3,043
300 + 0+ 1, 200 + 50+ 6, 800 +70 + 8.
Define the population, decide on the sample size (aka what percentage of that population)