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Virty [35]
3 years ago
15

4ttyu88 h ghiiiUuiyy...

Mathematics
2 answers:
frez [133]3 years ago
5 0

Answer:

hhoth3iohtioho3hoiho4hoihtio

   

UMMMMM....... OK XD

mr Goodwill [35]3 years ago
5 0

Answer:

the answer would beee kjlfjdck;fndocpfi;odnciofdljfkcx

Step-by-step explanation:

bc why not

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What is the measure of the indicated angle?
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110

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The proportion of brown M&M's in a milk chocolate packet is approximately 14%. Suppose a package of M&M's typically cont
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Answer:

Kindly check explanation

Step-by-step explanation:

Given the scenario above :

A) State the random variable.

The random variable is the p opoertion of brown M&M's in a milk chocolate packet.

B.) Argue that this is a binomial experiment.

Each trial is independent for a total number of 52 trials with a set probability of success at 0.14

C) probability that 6 M&M's are brown:.

P(x) = nCx * p^x * (1-p)^(n-x)

p = 0.14 ; (1 - p) = 0.86 ; n = 52 ; x = 6

P(x = 6) = 52C6 × 0.14^6 × 0.86^46

= 20358520 × 0.00000752954 × 0.00097035078

= 0.1487

D) P(x =25)

P(x = 25) = 52C25 × 0.14^25 × 0.86^27

= 477551179875952 × 449.987958058*10^(-24) × 0.01703955245

= 0.00000000366

E) P(x = 52)

P(x = 52) = 52C52 × 0.14^52 × 0.86^0

= 1 × 3968.78758299*10^(-48) × 1

= 3968.78758299*10^(-48)

F) yes it would be unusual, because such probability is extremely low. However, if a huge or substantial number of trials such may occur

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Hope it helped
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