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3 years ago

4ttyu88 h ghiiiUuiyy...

Mathematics

2 answers:

frez [133]3 years ago

5 0

Answer:

hhoth3iohtioho3hoiho4hoihtio

UMMMMM....... OK XD

mr Goodwill [35]3 years ago

5 0

Answer:

the answer would beee kjlfjdck;fndocpfi;odnciofdljfkcx

Step-by-step explanation:

bc why not

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Solve for x x+0.15x=3.45

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Write an equation in slope-intercept form for the line with slope -6 and y-intercept 5

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y=-6+5

Step-by-step explanation:

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Sarah received a gift in a rectangular box with a volume of 240 in3. If the base of the box was 20 in2, how tall was the box?

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3 years ago

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PLEASE HELP I AM DESPERATE!!!

Vilka [71]

Answer:

Statements:

m<b = 180 - m<a

m<c = 180 - m<d

m<b = m<c

180 - m<a = 180 - m<d

Reasons:

The measure of m<b is the angle of a straight line subtracted with m<a. The measure of m<c is the angle of a straight line subtracted with m<d. If m<a and m<d are equal, m<b and m<c are equal.

Step-by-step explanation:

We know, m<a = m<d

So, we need to prove m< b = m<c

Let's start by defining what b and c is

m<b + m<a = 180 This is because a straight line is 180 degrees

m<b = 180 - m<a

m<c + m<d = 180

m<c = 180 - m<d

With this, we can substitute in proof

m<b = m< c

180 - m<a = 180 - m<d

180 - m<a = 180 - m<a

Your welcome for the answer. Tell me if you have any questions in the comments section of this answer! If you could mark this answer as the brainliest, I would greatly appreciate it!

4 0

2 years ago

The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

Let X = number of hours spent per week on household chores

So, assuming data follows normal distribution; X ~ N( $\mu=28,\sigma^{2}=7^{2}$ )

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean hours = 28

$\sigma$ = standard deviation = 7 hours

n = sample of adults = 49

Let $\bar X$ = sample mean hours spent per week on household chores

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P( $\bar X$ > 26.75 hours)

P( $\bar X$ > 26.75 hours) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{26.75-28}{\frac{7}{\sqrt{49} } }$ ) = P(Z > -1.25) = P(Z < 1.25)

= 0.89435 {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

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3 years ago

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