Answer:
In the numbers mumbo jumbo, 76 is the minimum and 89 is the maximum. So it can look like this. (Fig A)
If you understood Fig A, the rest is easy.
There are one 76s, one 77s, four 78s, no 79s, four 80s, five 81s, no 82s, five 84s, four 85s, one 86s, two 87s, one 88s, and two 89s in the mumbo jumbo.
So the completed dot plot would look like Fig B. (I drew this in the computer and the dots aren't presicely balanced, but you'll get the idea)
Answer:
[see below]
Step-by-step explanation:
Quadrant One has a positive value for both x and y. (+ , +)
Quadrant Two has a negative x value. (- , +)
Quadrant Three has a negative value for both x and y. (- , -)
Quadrant Four has a negative y value. (+, -)
Therefore:
(2, -3) would be plotted in Q4. It does not lie on any axis.
(0, 8) would be on the positive y-axis. (0 is neither negative nor positive.)
(-1, -2) would be plotted in Q3. It does not lie on any axis.
(4, 7) would be plotted in Q1. It does not lie on any axis.
Answer:
8
Step-by-step explanation:
a A + b A where A is a matrix and a and b are scalars
( a+b) A
3+5 ![\left[\begin{array}{cc}-1&2\\4&-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%262%5C%5C4%26-5%5Cend%7Barray%7D%5Cright%5D)
= 8
Answer: -6
Step-by-step explanation: -|b-a|
-|-2-4|
-|-6|
-6
Once you get rid of the absolute value bars the negative sign is still outside of them making 6 negative again. Hope this helped! :P
Answer:
3x²+12x
Step-by-step explanation:
Expand the brackets
