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soldier1979 [14.2K]
3 years ago
7

8/10 - 3/4= answer this and ill give you the brainliest UWU

Mathematics
2 answers:
Mariulka [41]3 years ago
8 0

Answer: the answer be 1/20

Step-by-step explanation:

I hope it helps you :)

RideAnS [48]3 years ago
3 0

Answer:

1/20

Step-by-step explanation:

UWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWUUWU

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Lizette wanted to see if it would be possible to use a little less materials in a tea infuser but still not be required to be at
Oksi-84 [34.3K]

Considering the volume of a rectangular prism, since the new volume is greater than the filled volume, the new dimensions would work, and 90.29% of the infuser would be filled.

<h3>What is the volume of a rectangular prism?</h3>


The volume of a rectangular prism of length l, width w and height h is given by:

V = lwh.

The original dimensions are:

h = 7.9 cm, l = 3 cm, w = 1.5.

Hence the volume in cm³ was:

V = 7.9 x 3 x 1.5 = 35.55 cm³.

The infuser was filled to 80% capacity, hence:

Vf = 0.8 x 35.55 = 28.44 cm³.

For the new dimensions, we have that h = 7 cm, hence the volume is:

Vn = 7 x 3 x 1.5 = 31.5 cm³.

28.44/31.5 x 100% = 90.29%.

Since the new volume is greater than the filled volume, the new dimensions would work, and 90.29% of the infuser would be filled.

More can be learned about the volume of a rectangular prism at brainly.com/question/17223528

#SPJ1

4 0
2 years ago
Please show working out, thanks!
sveticcg [70]
3^2x = 2^3y = x/y = x/y
4 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
Round to the nearest Cent.
Westkost [7]
1. $.0999 = $.1

2. $2.0192 = $2.02

3. $21.5953 = $21.60

4. $35.6667 = $35.67

5. $1.3999 = $1.40

6. $25.3333 = $25.33
5 0
3 years ago
Read 2 more answers
The volume of a sphere is increasing at a constant rate of 141 cubic feet per minute. At the instant when the radius of the sphe
ch4aika [34]

Answer:

0.093 ft/min

Step-by-step explanation:

V = 4/3 π r³

Take derivative with respect to time:

dV/dt = 4π r² dr/dt

Plug in values:

141 = 4π (11)² dr/dt

dr/dt = 141 / (484π)

dr/dt ≈ 0.093

The radius is increasing at 0.093 ft/min.

6 0
3 years ago
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