Firstly , we will check continuity at x=1
we can use method
Suppose, f(x) is continuous at x=c
then it must satisfy
firstly , we can find limit
so, we get
now, we can find f(1)
so, we got
so, this is continuous at x=1
Hence , option-D...........................Answer
Let
be any integer. Then
In other words:
(1) If
is a multiple of 4, then
.
(2) If dividing
by 4 leaves a remainder of 1, then
, since
for some integer
, and from (1) we know that
(because, obviously,
is a multiple of 4).
(3) If instead you get a remainder of 2, then
. This follows from (1) as well.
.
(4) Finally, if you get a remainder of 3, then
.
The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.
Given a company has 200 machines. Each machine has a 12% probability of not working.
If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.
So
1) probability that 5 would not be working
C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵
≈ 0.18665
2) probability that at least one machine would be working
0.88⁴⁰ ≈ 0.00602
3) probability that all would be working
1 - 0.12⁴⁰ ≈ 1.0000
Learn more about probability here: brainly.com/question/24756209
#SPJ10
The Quotient is 8 and you would simplify if that's an option
if its not then I will tell you what else it could be
Answer:
The answer is the fourth option: 9 mm^3
Step-by-step explanation:
6/2=3
4/2=2
3/2=1.5
3*2*1.5=9
