1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleksandr-060686 [28]
3 years ago
6

Helpppp!! On which surface is the student not able to move the box?

Physics
1 answer:
LenKa [72]3 years ago
3 0

Answer:

d

Explanation:

i just took the quiz

You might be interested in
If a Sam goes above and beyond what is expected in her job duties, what might Sam's supervisor note on Sam's next evaluation?
leva [86]

Answer:

2

Exadadadwwwwwwwplanation:

4 0
3 years ago
Which ball has the greater acceleration at the instant of release
melisa1 [442]
I can't see either of them, so I must assume that they're both
far away from me, at different places in the solar system. 

So I can say with some assurance that whichever ball is on the
more massive planet will have greater acceleration when it's dropped. 
Its acceleration will be constant, from the instant of release until the
instant it hits the "ground" or whatever they call it on that planet.
3 0
4 years ago
Guys I really need help with these 2 questions , it's for my final plz help asap
mars1129 [50]

Answer:

(1) Initial speed, u=0

    Final speed, v=165.76m/s

    Average speed, v_a_v_g=82.87m/s

(2) Force of gravity, F_g=12.8\times10^1^5N

Explanation:

(1)

Given,

Distance, S=300meter

Time, t=3.62second

It is given that drag racer started at rest.

So Initial speed, u=0

Using Newton's second equation of motion,

S=ut+\frac{1}{2}at^2\\300=0+\frac{a\times3.62^2}{2} \\a=45.79m/s^2

Newton's first equation of motion,

v=u+at\\=0+45.79\times3.62\\=165.76 m/s

So, Final speed, v=165.76m/s

Average speed is defined as totle distance divided by totle time.

v_a_v_g=\frac{S}{t}\\=\frac{300}{3.62} \\=82.87m/s

So, Average speed, v_a_v_g=82.87m/s

(2)

Gravitation: It is the natural phenomenon in which two different bodies attract each other by virtue of their masses.

       According to Newton's law of gravitation, the force of attraction between two bodies is directly proportional to the masses of the bodies and inversely proportional to square of distance between centers of mass of the bodies.

                         F_g\propto\frac{m_1m_2}{r^2} \\F_g=G\frac{m_1m_2}{r^2}where Gis constant of proportionality and known as gravitation constant.

Given,

Mass of Jupiter, m_1=1.9\times10^2^7kg

Mass of Ganymede, m_2=1.48\times10^2^3kg

Distance between their centers of mass, r=1.21\times10^1^2meter

F_g=G\frac{m_1m_2}{r^2}\\=\frac{6.67\times10^-^1^1\times1.9\times10^2^7\times1.48\times10^2^3}{(1.21\times10^1^2)^2} \\=12.8\times10^1^5N

So, Force of gravity, F_g=12.8\times10^1^5N

7 0
3 years ago
What causes diffraction that results in a fuzzy glow around a full moon?
bagirrra123 [75]
Well, that's not actually "diffraction".

The fuzzy edge of the moon, and the added glow that's sometimes seen
around it, are all effects caused by the light passing through air before it
reaches you.

This gives you some idea of why astronomers go to such effort and
expense to get their telescopes above as much of the atmosphere as
possible ... placing all serious observatories on mountaintops, and even
putting telescopes in orbit.  It's all because the air does such a job on the
light that's trying to shine through it.  We have to make do with whatever's
left over after that.
6 0
3 years ago
An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reach
Gelneren [198K]

Answer:5 m/s^{2}

Explanation:

This problem is related to vertical motion, and the equation that models it is:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Isolating g and taking into account sin(90\°)=1 :

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

5 0
3 years ago
Other questions:
  • What is the first step in using a balance beam scale?
    10·1 answer
  • What does a line coming up and getting steeper represent on a distance/time graph?
    8·1 answer
  • This type of polarization occurs when light strikes the atoms of a material.
    6·2 answers
  • A large positively charged object with charge q + = 3.25 μC q+=3.25 μC is brought near a negatively charged plastic ball suspend
    12·1 answer
  • A jet plane passes over you at a height of 5870 m and a speed of Mach 1.47. (a) Find the Mach cone angle. (b) How long after the
    13·1 answer
  • Indicate whether the statement is true or false. If false, change the identified word or phrase to make me su
    14·2 answers
  • A ball is thrown upward from the edge of a cliff with an initial velocity of 6 m/s. (a) How fast is it moving 0.5 s later? In wh
    12·1 answer
  • An object with a potential energy of 981 J is placed at a height of 2m. What is the mass of the object?
    11·1 answer
  • A force of 10N acts on a car for 3 seconds. The impulse imparted on the car is
    7·1 answer
  • A. 65-year old emmetrope wearing +2.50D readers has a near point of accommodation of 25 cm. what is the near point accommodation
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!