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snow_tiger [21]
3 years ago
12

Boat A and Boat B have the same mass. Boat A’s velocity is three times greater than that of Boat B. Compared to the kinetic ener

gy of Boat B, the kinetic energy of Boat A is
A: one-third as much.
B: three times as much.
C: six times as much.
D: nine times as much.
Physics
2 answers:
elena55 [62]3 years ago
6 0

Answer:

The answer is B:three times as much.

Helen [10]3 years ago
3 0

Answer:

Explanation:

D. Nine times as much.

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2 years ago
The noise floor, also known as additive white Gaussian noise (AWGN), is a continuous noise level that appears over a wide spectr
harkovskaia [24]

Answer:

correct option is a. True

Explanation:

solution

the noise floor is AWGN ( additive white Gaussian noise )  

and when viewed in the frequency domain, it is the continuous noise level  

because as they have a  uniform power over all the frequency.

 

so that it is additive white Gaussian noise  

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4 0
3 years ago
if you run around a circle at 4.5 m/s and the circle has a radius of 7.7 m, what is your centripetal acceleration?
madreJ [45]

Answer:

Centripetal acceleration,

a_{c} =2.63\ m/s^{2} }

Explanation:

Centripetal acceleration:

Centripetal acceleration is the idea that any object moving in a circle, in something called circular motion, will have an acceleration vector pointed towards the center of that circle.

Centripetal means towards the center.

Examples of centripetal acceleration (acceleration pointing towards the center of rotation) include such situations as cars moving on the cicular part of the road.

An acceleration is a change in velocity.

Formula for Centripetal acceleration:

a_{c} =\frac{(velocity)^{2} }{radius}

Given here,

Velocity = 4.5 m/s

radius = 7.7 m

To Find :

a_{c} = ?

Solution:

We have,

a_{c} =\frac{(velocity)^{2} }{radius}

Substituting  given value in it we get

a_{c} =\frac{(4.5)^{2}}{7.7} \\\\a_{c} =\frac{20.25}{7.7}\\\\a_{c} =2.629\ m/s^{2} \\\\\therefore a_{c} =2.63\ m/s^{2

Centripetal acceleration,

a_{c} =2.63\ m/s^{2} }

7 0
3 years ago
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Answer:

N=62421972534 electrons

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Number of electrons transferred:  N=\frac{Q}{Q_{e} }=(-10*10^{-9} )/(-1,602*10^{-19})=62421972534 electrons

5 0
3 years ago
What is nuclear energy?
____ [38]

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