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gogolik [260]
3 years ago
9

A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars

combine.A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars combine. What is the magnitude of the final velocity of the combined cars?
Physics
1 answer:
shtirl [24]3 years ago
3 0
In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂

The final mass of the trains will be:
10,000 + 10,000 = 20,000 kg
Substituting the values into the equation:

10,000 * 3 = 20,000 * v
v = 1.5 m/s

The final velocity of the trains will be 1.5 m/s
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Answer:

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a is the acceleration of the body

By substituting the values we get, a = 2 m/s²

As acceleration is constant, we can use the below formula for calculating the final velocity of the object

v = u + a × t

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By substituting the values we get

v = 0 + 2 × 3 = 6 m/s

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Torque acting on the wheel about axis of rotation = 300 mm × 200 N =

60 N·m

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Assuming that the mass of spokes of the wheel to be negligible,

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Then,

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w_{f} = w_{i} + α × t

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w_{f} is the final angular velocity

w_{i} is the initial angular velocity

α is the angular acceleration

t is the time taken

w_{i} is 0 (∵ initially it starts from rest)

By substituting the values we get

w_{f} = 6·67 × 3 = 20 rad/s

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<u>Given data</u>

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                                                           η =   W ÷ Q₁  

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