A block of mass 22 kg is sliding along the ice at constant speed 5.0 m/s just ahead of it is q block of mass 29 kg sliding in th
1 answer:
Answer:
Answer:
New speed of the 22-kg block is 1.57 m/s
Explanation:
Mass of block
Mass of another block
Initial speed of the block
Initial speed of the another block
Initial speed of the another block
For conservation of momentum, we have
Substitute all the values and solving for final speed of the 22kg block is
new speed of the 22-kg block is 1.57 m/s
Couldnt write the answer so check picture
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Answer:
No
Explanation:
The force of tension exerted by the string on the rock acts as centripetal force, so its direction is always towards the centre of the circle.
However, the direction of motion of the rock is always tangential to the circle: this means that the force is always perpendicular to the direction of motion of the rock.
As we know, the work done by a force on an object is
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the force and the displacement
In this situation, F and d are perpendicular, so , therefore
and the work done is zero: