A block of mass 22 kg is sliding along the ice at constant speed 5.0 m/s just ahead of it is q block of mass 29 kg sliding in th
1 answer:
Answer:
Answer:
New speed of the 22-kg block is 1.57 m/s
Explanation:
Mass of block
Mass of another block
Initial speed of the block
Initial speed of the another block
Initial speed of the another block
For conservation of momentum, we have
Substitute all the values and solving for final speed of the 22kg block is
new speed of the 22-kg block is 1.57 m/s
Couldnt write the answer so check picture
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Answer:
0.51 m
Explanation:
Using the principle of conservation of energy, change in potential energy equals to the change in kinetic energy of the spring.
Kinetic energy, KE=½kx²
Where k is spring constant and x is the compression of spring
Potential energy, PE=mgh
Where g is acceleration due to gravity, h is height and m is mass
Equating KE=PE
mgh=½kx²
Making x the subject of formula
Substituting 9.81 m/s² for g, 1300 kg for m, 10m for h and 1000000 for k then
Answer:
The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is equal to 2 : 1
Explanation:
Detailed explanation and calculation is shown in the image below
