Answer:
Explanation:
The number of emails is multiplied by <em>4</em> every <em>9.1 weeks.</em>
Thus, since <em>Tobias initially sent the chain letter to 37 friends</em>, the number of letters will grow as per this geometric series:
Start: 37 letters
- In 2 × 9.1 weeks: 37 × (4)²
- In 3 × 9.1 weeks: 37 × (4)³
As you see, the exponent is the number of weeks divided by 9.1
Thus, if your variable is the number of weeks, t, then the exponent is t/9.1
And the exponential function, P(t) will be:

Answer:
2.1
Step-by-step explanation:
This involves trigonometry. Since we need to find the value of a, we need to find a trig equation with a as the numerator. Luckily, we have one, tan. So, tan(20) is equal to a/6, right. So, using a calculator, tan(20) is approximately equal to 0.363. This times 6 should equal a. This is approximately around 2.1. Thus our answer is 2.1
Answer:
x = 15 or x = - 
Step-by-step explanation:
Cross- multiplying gives
(14x + 6)(17x + 5) = 9x(27x + 11) ( expanding factors )
238x² + 172x + 30 = 243x² + 99x
rearrange into standard form : ax² + bx + c = 0
5x² - 73x - 30 = 0 ← in standard form
consider the factors of the product 5 × - 30 = - 150 which sum to the coefficient of the x-term (- 73 )
the factors are - 75 and + 2
Use these factors to split the middle term
5x² - 75x + 2x - 30 = 0 ( factor by grouping )
5x(x - 15) + 2(x - 15) = 0 ← take out the factor (x - 15)
(x - 15)(5x + 2) = 0
equate each factor to zero and solve for x
x - 15 = 0 ⇒ x = 15
5x + 2 = 0 ⇒ x = - 
For this case we must find 35% of 280.
Kerrie gets 10% and then 25%. So:
10% of 280:
280 ------------> 100%
x -----------------> 10%
Where "x" represents the amount given by 10% of 280.

Thus, 10% of 280 is 28.
Now, we find 25% of 280:
280 ------------> 100%
x -----------------> 25%
Where "x" represents the amount given by 25% of 280.

Thus, 25% of 280 is 70.
So we have that 35% of 280 is given by:

So, Kerrie's solution is correct.
Answer:
Option A
I think the answer is around 1.4 as you need to multiply the area by 1/9 after finding the real area.