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Dahasolnce [82]
3 years ago
9

Help pls Ill thank you and give you brainlist

Mathematics
2 answers:
navik [9.2K]3 years ago
8 0
Y > x-1/3 + 1

Have a nice day
Tamiku [17]3 years ago
7 0
-y>10x-2 hope this helped :)
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a local park is in the shape of a square. a map of the local park is made with the scale 1 inch to 200 feet. if the park is show
vladimir2022 [97]

Answer:

600 ft per side

Step-by-step explanation:

1 in = 200 feet

12 in = 1 foot

12 in * 200 ft= 2400 ft

2400/4 = 600 ft per side

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3 years ago
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Which of the following are true statements about any regular polygon? Check all that apply. A. It is a quadrilateral. B. All of
sesenic [268]
A regular polygon is a closed figure 
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4 years ago
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Jackson deposited $5000 at 3.8% interest compound continuously when he was 18 years old. How much will be in the account when he
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Answer:

$11535.60

Step-by-step explanation:

We have been given that Jackson deposited $5000 at 3.8% interest compound continuously when he was 18 years old.

To find the amount that Jackson will earn when he is 40 years old, we will use compound interest formula.

A=P\cdot e^{rT}

A= Amount after T years.

P= Principal amount.

e= Mathematical constant e.

r= Interest rate (in decimal form).

T=  Time in years.

Let us convert our given interest rate into decimal form.

3.8\text{ percent}=\frac{3.8}{100}=0.038

Upon substituting our given values in above formula we will get,

A=5000\cdot e^{(0.038\times (40-18))}    

A=5000\cdot e^{(0.038\times 22)}

A=5000\cdot e^{0.836}

A=5000\cdot 2.307120015126555      

A=11535.600075632775\approx 11535.60

Therefore, Jackson will have $11535.60 in his account when he is 40 years old.

4 0
3 years ago
A student finds an object with a mass of 64.54g and a volume of 14cm3. Find the density of the object.
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Answer:

4.61 g/cm3

Step-by-step explanation:

density is mass divided volumen

density \:  =  \frac{64.54g}{14 {cm}^{3} }  = 4.61 \frac{g}{ {cm}^{3} }

7 0
4 years ago
Which of these statements is true for
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If x = 1 then f(x) = (1/10)^1 = 1/10

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4 years ago
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