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3 years ago

Using eight eights and addition only, can you make 1000?

Mathematics

2 answers:

Serga [27]3 years ago

6 0

Answer:

..........................................................................................................................................................................................No

Step-by-step explanation:

Rus_ich [418]3 years ago

6 0

Answer:

Step-by-step explanation:

yes

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From 2006 to 2010, the population of a town declined to 22,000. The population is expected to continue to decline at a rate of 2

Kruka [31]

Assume that a certain population is P. If the population has decreased 2.8% at the end of one year, this means that the population now is

100%P-2.8%P=97.2%P. Thus a decrease of 2.8% can means a multiplication by 97.2%, which is 97.2/100=0.972.

So, assume the population in 2006 was P. Then the population in 2007 was

0.972P. Similarly, we can see that the population in 2008 was 0.972(0.972P).

The population in 2009 the population was 0.972(0.972(0.972P)), which is $(0.972)^3P$ .

Finally, in the end of 2010 the population was $(0.972)^4P$ .

The decline of the population from 2006 to 2010 was 22,000. This means that

$P-(0.972)^4P=22,000$ . Factorizing P we have:

$P(1-(0.972)^4)=22,000$ . We can calculate $(0.972)^4=0.8926$ , thus

$P= \frac{22,000}{1-0.8926}= \frac{22.000}{0.1074}= 204,842$ .

We saw that the population after the n'th year after 2006 was $(0.972)^4P$ .

2040 is the (2040-2006)=34th year after 2006, so the population in 2040 will be
$(0.972)^{34}P=(0.972)^34\cdot204,842$ .

$(0.972)^{34}=(((((0.972)^2)^2)^2)^2)^2\cdot(0.972)^2=0.4\cdot0.9448\approx0.378$

(to calculate $((((0.972)^2)^2)^2)^2)^2$ : 0.972_*_=*_=*_=*_=*_=, one *_= for each 2)

Thus, the population in 2040 was 0.378*204,842=77,430.

3 0

4 years ago

Read 2 more answers

Find all missing sides and angles

Lorico [155]

Answer:

I'm doing a challenge. This is my answer. IDK.

Step-by-step explanation:

3 0

4 years ago

We solve equations with decimals just like we solve equations ____

matrenka [14]

So what's your question?

4 0

3 years ago

Help pls I’m in need

snow_tiger [21]

Answer:

Step-by-step explanation:

Bro.....

IDK

8 0

4 years ago

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Complete the table, for the following investments, which shows the performance (interest and balance) over a 5-year period.

sergiy2304 [10]

Answer:

After 5 years of investment, Suzanne will have $ 4,400 in her account, while Derek will have $ 4,416.32 in his account.

Step-by-step explanation:

Since Suzanne deposits $ 4000 in an account that earns simple interest at an annual rate of 2%, and Derek deposits $ 4000 in an account that earns compound interest at an annual rate of 2% and is compounded annually., Both for a period of 5 years, to determine how much money each one will have in their account after 5 years, the following calculation must be made:

Suzanne:

((4,000 x 0.02) x 5) + 4,000 = X

(80 x 5) + 4,000 = X

400 + 4,000 = X

4,400 = X

Derek:

4,000 x (1 + 0.02 / 1) ^ 5x1 = X

4,000 x 1.02 ^ 5 = X

4,416.32 = X

Thus, after 5 years of investment, Suzanne will have $ 4,400 in her account, while Derek will have $ 4,416.32 in her account.

5 0

3 years ago