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GREYUIT [131]
3 years ago
14

NEED HELP ASAP!!

Mathematics
1 answer:
pantera1 [17]3 years ago
8 0

Answer:

t=1/30 h = 2 min

Step-by-step explanation:

d = vt

system of equations:

d = 13t

d - 2/5 = t       ->     d = t+2/5

Solve

13t = t +2/5

t = 1/30 h = 60 min / 30 = 2 min

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Answer:

884736

Step-by-step explanation:

Multiply using the order of operations, from left to right.

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Does anyone have a website to cheat on
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No i do for other stuff but not this and the answer is 18

Step-by-step explanation:

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3 years ago
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
Help me :) !
m_a_m_a [10]

Answer:

69

Step-by-step explanation:

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2 years ago
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What is the solution for the system of equations? Use the substitution method to solve. y=5−3x 5x−4y=−3
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The answer is x=1 and y =2
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3 years ago
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