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svet-max [94.6K]
3 years ago
6

Given that abcd is a rhombus prove ac bisects BCD 80 points please answer​

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Step-by-step explanation:

<u>See the missing reasons, in order from top to bottom:</u>

  • 1. Definition of rhombus
  • 2. Definition of congruent
  • 3. Given
  • 4. Definition of bisects
  • 5. Reflexive property
  • 6. SSS (three sides congruency)
  • 7. CPCTC
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Please help me on this problem
butalik [34]

Answer:

I think the answer would be -21%!

Step-by-step explanation:

-4/5 = -0.8 would be behind -.05

- 0.7 would be behind -.05

-21% = -0.21 correct answer

- square root of 1 = -1 too far from 0

Good Luck. Hope this helped.

8 0
3 years ago
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Use the disk method or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs
JulsSmile [24]

Answer:

1) V = 12 π  ㏑ 3

2) \mathbf{V = \dfrac{328 \pi}{9}}

Step-by-step explanation:

Given that:

the graphs of the equations about each given line is:

y = \dfrac{6}{x^2}, y =0 , x=1 , x=3

Using Shell method to determine the required volume,

where;

shell radius = x;   &

height of the shell = \dfrac{6}{x^2}

∴

Volume V = \int ^b_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = \int ^3_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = 12 \pi \int ^3_{x-1} \dfrac{1}{x} \ dx

V = 12 \pi ( In \ x ) ^3_{x-1}

V = 12 π ( ㏑ 3 - ㏑ 1)

V = 12 π ( ㏑ 3 - 0)

V = 12 π  ㏑ 3

2) Find the line y=6

Using the disk method here;

where,

Inner radius r(x) = 6 - \dfrac{6}{x^2}

outer radius R(x) = 6

Thus, the volume of the solid is as follows:

V = \int ^3_{x-1} \begin {bmatrix}  \pi (6)^2 - \pi ( 6 - \dfrac{6}{x^2})^2  \end {bmatrix} \ dx

V  =  \pi (6)^2 \int ^3_{x-1} \begin {bmatrix}  1 - \pi ( 1 - \dfrac{1}{x^2})^2  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  1 -  ( 1 + \dfrac{1}{x^4}- \dfrac{2}{x^2})  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  - \dfrac{1}{x^4}+ \dfrac{2}{x^2} \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  {-x^{-4}}+ 2x^{-2} \end {bmatrix} \ dx

Recall that:

\int x^n dx = \dfrac{x^n +1}{n+1}

Then:

V = 36 \pi ( -\dfrac{x^{-3}}{-3}+ \dfrac{2x^{-1}}{-1})^3_{x-1}

V = 36 \pi ( \dfrac{1}{3x^3}- \dfrac{2}{x})^3_{x-1}

V = 36 \pi \begin {bmatrix} ( \dfrac{1}{3(3)^3}- \dfrac{2}{3}) - ( \dfrac{1}{3(1)^3}- \dfrac{2}{1})    \end {bmatrix}

V = 36 \pi (\dfrac{82}{81})

\mathbf{V = \dfrac{328 \pi}{9}}

The graph of equation for 1 and 2 is also attached in the file below.

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4 years ago
What is the solution to the equation 1/4x-1/8=7/8+1/2
Dmitrij [34]

Answer: x=6

Step-by-step explanation:

1) add 1/8 to both sides

2) divide both sides by 1/4

3) 1.5/.25= 6

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4 years ago
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xz_007 [3.2K]
<span>{x | x < 0} and {x | x > 0}</span>
8 0
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Find the whole amount of 8% of 72 cm
IrinaVladis [17]

Answer:

5.76

Step-by-step explanation:

7 0
3 years ago
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