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3 years ago

Given that abcd is a rhombus prove ac bisects BCD 80 points please answer

Mathematics

1 answer:

PolarNik [594]3 years ago

4 0

Step-by-step explanation:

See the missing reasons, in order from top to bottom:

1. Definition of rhombus
2. Definition of congruent
3. Given
4. Definition of bisects
5. Reflexive property
6. SSS (three sides congruency)
7. CPCTC

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Which instruments listed below are examples of the classification idiophone?

rjkz [21]

Idiophone means an instrument that will produce a sound when being struck.
so the answer is B.

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3 years ago

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Find the volume of the following compound shape.

Bess [88]

<h3>Given:</h3>

Cone
Cylinder

<h3>Volume of the cone:</h3>

$v = \frac{1}{3} \pi {r}^{2} h$

$v = \frac{1}{3} \times \pi \times {10}^{2} \times 10$

$v = 1047.20 \: {cm}^{3}$

<h3>Volume of the cylinder:</h3>

$v = \pi {r}^{2} h$

$v = \pi \times {10}^{2} \times 10$

$v = 3141.59 \: {cm}^{3}$

<h3>Total volume:</h3>

$v = 1047.20 + 3141.59$

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Hence, the volume of the given cone shape is 4188.79 cubic centimeters.

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2 years ago

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In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to

babymother [125]

Answer:

dA/dt = k1(M-A) - k2(A)

Step-by-step explanation:

If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)

Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:

Rate Memorized = k1(M-A)

Where k1 is the constant of proportionality for the rate at which material is memorized.

At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:

Rate forgotten = k2(A)

Where k2 is the constant of proportionality for the rate at which material is forgotten.

Finally, the differential equation for the amount A(t) is equal to:

dA/dt = Rate Memorized - Rate Forgotten

dA/dt = k1(M-A) - k2(A)

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3 years ago

Janet had 3/5 yd of material. she used 1/3 of it for a hat. How much material did she use? explain how you got your answer.

9966 [12]

Answer:

Think of the total as 1/5 + 1/5 + 1/5 = 3/5

You have THREE fifths of material.

You use ONE of those fifths.

That leaves you with TWO fifths.

Step-by-step explanation:

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3 years ago

Complete the following statement: f(3)=_____

victus00 [196]

Using this equation, f(3) = 23.

In order to find the value of f(3), we need to take the f(x) equation and put 3 everywhere we see x. Then we follow the order of operations to solve. So, let's start with the original.

f(x) = 2x^2 + 5sqrt(x - 2)

Now place 3 in for each x.

f(3) = 2(3)^2 + 5sqrt(3 - 2)

Now square the 3.

f(3) = 2(9) + 5 sqrt(3 - 2)

Do the subtraction inside of the parenthesis.

f(3) = 2(9) + 5sqrt(1)

Take the square root

f(3) = 2(9) + 5(1)

Multiply.

f(3) = 18 + 5

And add.

f(3) = 23

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3 years ago

Given that abcd is a rhombus prove ac bisects BCD 80 points please answer​

Given that abcd is a rhombus prove ac bisects BCD 80 points please answer