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Colt1911 [192]
3 years ago
5

Can someone answer this please

Mathematics
2 answers:
Nana76 [90]3 years ago
6 0
Area is trapezium =
A=1/2h(a+b)

84=1/2(6)(7+b)

84=3(7+b)

84=21+3b

3b=84-21

B=63/3

B= 21 cm

I’m sorry if my answer turned out to be wrong but I tried my best so best of luck !!
LiRa [457]3 years ago
5 0

Answer:

x = 14

Step-by-step explanation:

Please note, the word trapezium is a synonym for the word trapezoid.

This problem gives one the area of the trapezoid, a well as one of the measurements of a base and the height of the figure. One is asked to find the length of the other base. This can be done by using the formula to find the area of a trapezoid. This formula is the following,

A=(h)(\frac{b_1+b_2}{2})

Where (A) represents the area of a trapezoid, (b_1) and (b_2) represents the bases and (h) represents the height. Substitute in the given values and solve for the unknown base.

b_1=7\\h=6\\A=84

A=(h)(\frac{b_1+b_2}{2})\\

Substitute,

84=6(\frac{7+b_2}{2})\\

Inverse operations,

84=6(\frac{7+b_2}{2})

14=\frac{7+b_2}{2}

28=7+b_2

14=b_2

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3 years ago
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

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B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

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5 0
3 years ago
Please help me with this question??m
Keith_Richards [23]

Answer:

75

Step-by-step explanation:

f(1) = 7

f(n) = 3f(n-1) + 3

So what you are trying to do here is find the recursive value (that's what it is called) for f(n). Computers love this sort of thing, but we humans have to do it slowly and carefully.

So let's try f(2)

That means that f(2) = 3*f(n-1) + 3

but if f(2) is used it means that you have to know f(2-1) which is just f(1) and we know that.

so f(2) = 3*f(1)+3

f(2) = 3*7 + 3

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f(2) = 24

Now do it again. We now know F(2), so we should be able to find f(3)

f(3) = 3*f(3 - 1) + 3  

f(3) = 3*f(2) + 3      We know that f(2) = 24

f(3) = 3* 24 + 3

f(3) = 72 + 3

f(3) = 75

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2 years ago
Find the Function and Solution.
ser-zykov [4K]

Answer:

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Step-by-step explanation:

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y= (3/16)-(5/8)

y= (-7/16)

I hope this is right, im not 100% sure

4 0
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