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mylen [45]
3 years ago
11

Connor has hired two painters to paint his house. The first painter charges $12 an hour and the second painter charges $11 an ho

ur. It will take 15 hours of labor to paint the house. A. Wrote a polynomial to represent the total cost of the job if the first painter does x hours of work. B. Write a polynomial to represent the total cost of the job if the second painter does y hours of labor.
Mathematics
1 answer:
schepotkina [342]3 years ago
7 0

Answer:

Cost = cost of first painter + cost of second painter

      = $12/hr * hours worked  + $11 * hours worked

   where x is the hours the first painter works

C(x) = 12 x + 11 ( 15 - x)

       = 12 x + 165 - 11x

        = x + 165

C(x,y) = 12 x + 11 y

   where y = 15  - x because the total hours is 15

Step-by-step explanation:

Lmk if I need to explain

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Haley is camping and needs to go from the campground to the waterfall. She hikes 3 miles north and 7 miles east. What is the sho
miskamm [114]

Answer:

7.61 miles

Step-by-step explanation:

Given that,

Haley hikes 3 miles north and 7 miles east.

We need to find the shortest distance from the campground to the waterfall. Let the distance is D.

It can be calculated as follows :

D=\sqrt{3^2+7^2}\\D=7.61\ miles

So, the shortest distance from the campground to the waterfall is 7.61 miles.

3 0
3 years ago
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viva [34]

Answer:

r = 10 cm

Step-by-step explanation:

r² = 8² + 6²

r² = 64 + 36 = 100

r = 10 cm

8 0
3 years ago
Read 2 more answers
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

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* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
Read 2 more answers
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bija089 [108]

Answer:

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Step-by-step explanation:

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Sindrei [870]

Answer:

Do you want to know the surface area of the triangle or the perimeter of the triangle?

Step-by-step explanation:

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4 0
3 years ago
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