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PIT_PIT [208]
2 years ago
13

Point B has coordinates ​(3​,2​). The​ x-coordinate of point A is −6. The distance between point A and point B is 15 units. What

are the possible coordinates of point​ A?
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0

Answer:

Distance between two points= √(x2-x1)²+(y2-y1)²

D= 15units

Let "k" be the y-coordinate of A

A(-6,k)

B(3,2)

15= √(3--6)²+(2-k)²

Taking square of both sides to eliminate the square root.

15²=(9)²+(2-k)²

225=81+4-4k+k²

k²-4k - 140=0

Using Quadratic Formula to evaluate

k= 14 or k=-10

The Possible coordinates of A are

(-6,14) or (-6,-10)

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yan [13]
Constant of Proportionality = d/t = 90/2 = 45 mph

In short, Constant of Proportionality would be: 45 miles per hour.

Here, d/t = 45
d = 45t

In short, Your Equation would be: d= 45t

Hope this helps!


5 0
3 years ago
How do you simplify 3 1/4 x 3/5 someone please help me
kifflom [539]

Answer:

We want to simplify:

(3 + 1/4)*(3/5)

The first step is to write the first term as a single rational number.

We know that:

3*1 = 3

and 4/4 = 1

then:

3*1 = 3*(4/4) = (3*4)/4 = 12/4

We do this because we want to have the same denominator in both numbers, so we can directly add them.

Then we get:

(3 + 1/4)*(3/5) = (12/4 + 1/4)*(3/5) = (13/4)*(3/5)

And remember that in the multiplication of rational numbers the numerator are multiplied together and the same for the denominators, then we get:

(13/4)*(3/5) =  (13*3)/(4*5)

If we solve the multiplications we get:

(13*3)/(4*5) = (39/20)

Now, we can notice that in the numerator we have two prime numbers, 13 and 3.

And in the denominators, we have a 4 (which is equal to 2*2) and a 5.

So the prime numbers in the numerator and the denominator are all different, this means that we can not simplify it furthermore.

Then we have:

(3 + 1/4)*(3/5) = (39/20)

6 0
3 years ago
The Suarez family paid $15.75 for 3 movie tickets. How much would they have paid for 12 tickets?
Serjik [45]

Answer:

$63

Step-by-step explanation:

15.75 / 3 = 5.25

5.25 is what each ticket was worth

5.25 * 12 = 63

8 0
3 years ago
Read 2 more answers
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KATRIN_1 [288]
It would be in the top left corner
5 0
3 years ago
Read 2 more answers
The coordinates of the preimage are: A(8,8) B(10,6) C(2,2) We want to reflect over y=−1 first. Our new coordinates are: A′(8, )
WITCHER [35]

Answer:

1)A'(8,-10), B'(10,-8), C'(2,-4)

2)A''(8,-4), B''(10,-6), C''(2,-10

Step-by-step explanation:

Given:

Points A(8,8) B(10,6) C(2,2)

reflection over y=-1

Perpendicular distance between points y-coordinates of points (A, B and C) and y=-1 are 9,7 and 3

after reflections, the perpendicular distance will be 18,14,6 and the points will be at

A'(8,-10), B'(10,-8), C'(2,-4)

Now  

Points A(8,-10), B(10,-8), C(2,-4)

reflection over y=−7

Perpendicular distance between points y-coordinates of points (A, B and C) and y=-7 are 3,1 and 3

after reflections, the perpendicular distance will be 6,2,6 and the points will be at

A''(8,-4), B''(10,-6), C''(2,-10) !

8 0
3 years ago
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