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ziro4ka [17]
3 years ago
12

How does the atomic radius of an element is related to its metallic character

Chemistry
1 answer:
Aneli [31]3 years ago
5 0

Answer:

The large the atomic radius the more the metallic character of elements

Explanation:

The atomic radius is related to the metallic character in a way that the larger the atomic radius, the more metallic a body becomes.

Therefore, as we go down a group, metallic character increases.

  • Metallic character relies on the ability and willingness of an atom to share its valence electrons.
  • As the size of an atom becomes large, the more metallic it is and the more its metallic character.
  • In some other cases this character is known as electropositivity.
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The galvanic cell illustrated above generates a potential of +1.10V. For the construction of a second galvanic cell (not shown),
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Answer:

The initial  E°  for the second cell is the same as for the first cell.

Explanation:

Because the overall chemical reaction that occurs in the cell does not change.

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3 years ago
The active ingredient in aspirin is acetylsalicylic acid. A 2.79 g sample of acetylsalicylic acid required 30.15 mL of 0.5137 M
vivado [14]

Answer:

Molar mass = 180 g/mol

Ka = 3.31x10⁻⁴

Explanation:

Because the acetylsalicylic is a monoprotic acid, it only leaves 1 mol of H⁺ in the reaction, so, it's necessary 1 mol of NaOH for each 1 mol of acetylsalicylic acid. The number of moles of NaOH is the volume, in L, multiplied by the concentration:

n = 0.03015*0.5137 = 0.01549

Which is also the number of moles of the acid. The molar mass is the mass, in g, divided by the number of moles:

M = 2.79/0.01549

M = 180 g/mol

After reacting with the base, the conjugate base of the acid will be formed, and the equilibrium between the acid form (HA) and the conjugate base (A⁻) is a buffer. It formed 0.01549 moles of A⁻, which will react with the moles of H⁺ from HCl to form HA.

nH⁺ = nHCl = 0.01741*0.448 = 0.0078 mol

A⁻           +       H⁺            ⇄   HA

0.01549     0.0078                 0        Initial

-0.0078     -0.0078         +0.0078   Reacts

0.0078            0                0.0078   Equilibrium

For a buffer, the pH can be calculated by the Handerson-Halsebach equation:

pH = pKa + log[A⁻]/[HA]

Because the volume is the same, we can use the number of moles instead of the concentration:

3.48 = pKa + log(0.0078/0.0078)

pKa = 3.48

pKa = -logKa

Ka = 10^{-pKa}

Ka = 10^{-3.48}

Ka = 3.31x10⁻⁴

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3 years ago
7.23 x 10^24 Al atoms =​
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Answer:

12.01 moles

Explanation:

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aleksley [76]
The answer is Abecaue it is the most specific on how
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OleMash [197]

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Explanation:

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