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Ymorist [56]
4 years ago
10

A 10.00 g sample of a soluble barium salt is treated with

Chemistry
1 answer:
icang [17]4 years ago
8 0
(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt 

<span>(10.0 g) / (0.0480 mol) = 208.3 g/mol </span>
<span>So it must have been BaCl2.

I think it letter A. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>
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