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Solnce55 [7]
3 years ago
11

Numbers 43 and 44 can I help with them

Mathematics
2 answers:
Genrish500 [490]3 years ago
7 0
D and a is the answer I'm pretty sure. Hope this helps!
alekssr [168]3 years ago
6 0
B. And then A. Hope this helps!
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If I have 200,000,000,000 pounds how many tons is that
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1 ton= 2,000 ponds. Thus 200,000,000,000 divided by 2,000 is 100,000,000
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2 years ago
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term x^2, which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form f(x)=ax^2+bx+c is given by the expression: x_v=\frac{-b}{2a}

Since in our case a=1 and b=5, we get that the x-position of the vertex is: x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the x_v=-\frac{5}{2}. Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

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2 years ago
Method for constructing the circle that inscribed a triangle
AleksAgata [21]

Answer:

Radius = incenter → peprpendicular to one side of the triangle

Step-by-step explanation:

  1. Bisect one of the angles
  2. Bisect another angle
  3. Where those two lines cross is the center of the inscribed circle, called the incenter
  4. Construct a perpendicular from the center point to one side of the triangle
  5. Place compass on the center point, adjust its length to where the perpendicular crosses the triangle, and draw your inscribed circle!
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PLS help timed! which graph represents the solution of y<x2-1 and x>y2-3?​
miv72 [106K]

Answer:

y minus 3 = 2x plus 1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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