Answer:
7
Step-by-step explanation:
Reflection is a rigid transformation, so the side length does not change.
A'B' = 7
Time is 4 hrs., coffee is 0 cups. Point (4,0)
So A
Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
Answer:
- The general solution is
- The error in the approximations to y(0.2), y(0.6), and y(1):
Step-by-step explanation:
<em>Point a:</em>
The Euler's method states that:
where
We have that , , ,
- We need to find for , when , using the Euler's method.
So you need to:
- We need to find for , when , using the Euler's method.
So you need to:
The Euler's Method is detailed in the following table.
<em>Point b:</em>
To find the general solution of you need to:
Rewrite in the form of a first order separable ODE:
Integrate each side:
We know the initial condition y(0) = 3, we are going to use it to find the value of
So we have:
Solving for <em>y</em> we get:
<em>Point c:</em>
To compute the error in the approximations y(0.2), y(0.6), and y(1) you need to:
Find the values y(0.2), y(0.6), and y(1) using
Next, where are from the table.