Which choice best explains how global winds are formed?

When the contour lines are farther apart, is the slope more gradual or gentle.

nignag [31]

Hi Zyshoun32,

Your Question:

When the contour lines are farther apart, is the slope more gradual or gentle.

Answer:

<u>When the slope is more gradual the farther the contour lines are.</u>

When the slope is more steeper the closer the contour lines are.

4 0

3 years ago

A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?

Anni [7]

Answer:

Explanation:

The mass of the ball can be found by using the formula

$m = \frac{2k}{ {v}^{2} } \\$

v is the velocity

k is the kinetic energy

From the question we have

$m = \frac{2(3.10)}{ {6.70}^{2} } = \frac{6.20}{44.89} \\ = 0.138115...$

We have the final answer as

Hope this helps you

7 0

3 years ago

What is chemistry the study of?

IRINA_888 [86]

Chemistry is the study of substances—that is, elements and compounds.

8 0

3 years ago

Read 2 more answers

How many liters of oxygen are required to completely react with 2.0 liters of CH4 at30 °C and 3.0 atm?CH4(g) + 2O2(g) → CO2(g) +

Dominik [7]

1) Write the chemical equation.

$CH_4+2O_2\rightarrow CO_2+2H_2O$

2) List the known and unknown quantities.

Sample: CH4.

Volume: 2.0 L.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Moles: <em>unknown</em>.

3) Moles of CH4.

<em>3.1- Set the equation.</em>

$PV=nRT$

<em>3.2- Plug in the known values and solve for n (moles).</em>

$(3.0\text{ }atm)(2.0\text{ }L)=n*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)$ $n=\frac{(3.0\text{ }atm)(2.0\text{ }L)}{(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}=$ $n=0.24\text{ }mol\text{ }CH_4$

4) Moles of oxygen that reacted.

The molar ratio between CH4 and O2 is 1 mol CH4: 2 mol O2.

$mol\text{ }O_2=0.24\text{ }CH_4*\frac{2\text{ }mol\text{ }O_2}{1\text{ }mol\text{ }CH_4}=0.48\text{ }mol\text{ }O_2$

5) Volume of oxygen required.

Sample: O2.

Moles: 0.48 mol.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Volume: <em>unknown</em>.

<em>5.1- Set the equation.</em>

$PV=nRT$

<em>5.2- Plug in the known values and solve for V (liters).</em>

$(3.0\text{ }atm)(V)=0.48\text{ }O_2*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)$ $V=\frac{(0.48\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(303.15\text{ }K)}{3.0\text{ }atm}$ $V=3.98\text{ }L$

3.98 L of O2<em> is required to react with 2.0 L CH4.</em>

.

6 0

2 years ago

List three different types of chemical reactions, write the generic description, and give a brief description of each.

slava [35]

Explanation:

Combination or synthesis reaction
Decomposition or cracking reaction
Single replacement or single displacement

A combination or synthesis is a type of reaction that involves the formation of a single product from tow or more reactants:

K + J → KJ

The formation of a single compound form the union of their constituent element falls into this category of reaction.

The large and negative heat of formation is the driving force for this reaction.

A decomposition or cracking reaction is one in which two or more products are formed from a single reactant:

TK → T + K

The breaking down o a compound into its individual components like elements and other compounds falls into this category.

The driving force for this type of reaction is the high positive heat of formation and instability of the compound.

A single replacement or single displacement reaction is one in which a substance is replacing another.

TO + P → TP + O

The replacement of a metallic ion in solution by a metal atom higher in the activity series than the metal in a solution falls into this category of reaction.

learn more:

Chemical reaction brainly.com/question/6281756

#learnwithBrainly

3 0

4 years ago