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levacccp [35]
3 years ago
10

when carbon dioxide is bubbled through lime water the solution first turn milky and to colour less . Explain why these changes o

ccur​
Chemistry
1 answer:
Annette [7]3 years ago
5 0

Answer:

When excess of carbon dioxide is passed in lime water, calcium carbonate is converted to calcium bicarbonate which is soluble, hence the milkiness due to calcium carbonate disappears.

Explanation:

Ca(OH)2+CO2 → CaCO3 (Milkiness) ↓+H2O

CaCO3+H2O+CO2 → Ca(HCO3)2 (soluble)

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What gas is used in respiration​
myrzilka [38]

Answer:

Los pulmones y el aparato respiratorio nos permiten respirar. Permiten la entrada de oxígeno en nuestros cuerpos (inspiración o inhalación) y expulsan el dióxido de carbono (expiración o exhalación). Este intercambio de oxígeno y dióxido de carbono recibe el nombre de "respiración"

La función del aparato respiratorio es mover dos gases: <em>el oxígeno y el dióxido de carbono</em>

Explanation:

6 0
3 years ago
4. How many milligrams are in 5.25 x 10-13 kg?<br><br> the “-13” is an exponent
rusak2 [61]

5. 25 x 10⁻⁷mg

Explanation:

This is mass conversion from mg to kg;

The kg is a quantity of mass used to measure the amount of matter in a substance.

   Given mass = 5.25 x 10⁻¹³kg

The kilo-  is a prefix that denotes 10³

  therefore;

         1000g = 1kilogram

 the milli-  is a prefix that denotes 10⁻⁻³

       1000mg = 1g

Now that we know this, we can convert:

   5.25 x 10⁻¹³kg  x \frac{1000g}{1kg}  x \frac{1000mg}{1g}   =  5. 25 x 10⁻¹³ x 10⁶mg

      =  5. 25 x 10⁻⁷mg

learn more:

Conversion brainly.com/question/1548911

#learnwithBrainly

8 0
3 years ago
How much concentrated 5.0M nitric acid is needed to prepare 50 mL of a 1.0 M solution?
Ksivusya [100]

Explanation:

Volume is the quantity of three-dimensional  

6 0
2 years ago
What is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa
Nezavi [6.7K]

60.7 ml is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa.

Explanation:

Data given:

V1 = 75 ml

T1 = 30 Degrees or 273.15 + 30 = 303.15 K

P1 = 91 KPa

V2  =?

P2 = 1 atm or 101.3 KPa

T2 = 273.15 K

At STP the pressure is 1 atm and the temperature is 273.15 K

applying Gas Law:

\frac{P1VI}{T1}= \frac{P2V2}{T2}

putting the values in the equation of Gas Law:

V2 = \frac{P1V1T2}{P2T1}

V2 = \frac{91 X 75 X 273.15}{303.15 X 101.3}

V2 = 60.7 ml

at STP the volume of carbon dioxide gas is 60.7 ml.

4 0
3 years ago
25 POINTS:)
Digiron [165]
I suppose that the answer is A
6 0
3 years ago
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