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levacccp [35]
3 years ago
10

when carbon dioxide is bubbled through lime water the solution first turn milky and to colour less . Explain why these changes o

ccur​
Chemistry
1 answer:
Annette [7]3 years ago
5 0

Answer:

When excess of carbon dioxide is passed in lime water, calcium carbonate is converted to calcium bicarbonate which is soluble, hence the milkiness due to calcium carbonate disappears.

Explanation:

Ca(OH)2+CO2 → CaCO3 (Milkiness) ↓+H2O

CaCO3+H2O+CO2 → Ca(HCO3)2 (soluble)

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the answer is c

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How do you calculate the mass of a product when the amounts of more than one reactant are given?
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5 0
3 years ago
Read 2 more answers
Julissa combined baking soda and calcium chloride solution in a beaker. she observed bubbling and a white solid formed. Julissa
Mamont248 [21]

Answer:

A

Explanation:

With chemical reactions, there are various factors that affect the rate of the reaction. One of these is temperature.

When you raise the temperature, the reaction will move faster. Why? Temperature is directly correlated with the kinetic energy (basically, the energy that makes the particles move). Higher temperatures mean higher kinetic energies. Particles with higher kinetic energies move faster, which makes them more likely to collide. When collisions occur more frequently, the reaction follows through more quickly.

Thus, when Julissa warms the solutions, she will see that bubbling and white solid formation (the products of the reaction) occus faster. So, the answer is A.

Hope this helps!

3 0
3 years ago
One mole of carbon (12.0 g) in the form of crystalline graphite is burned at 25◦C and 1.000 atm pressure to form CO2(g). All of
iogann1982 [59]

Answer:

T₂ = 43.46 °C  

Explanation:

Given that:

The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)

It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J

Heat gain by water = Heat lost by the reaction

Thus,    

m_{water}\times C_{water}\times \Delta T=Q

For water:  

Mass of water  = 5100 g

Specific heat of water = 4.18 J/g°C  

T₁ = 25 °C  

T₂ = ?

Q = 393500 J

So,

5100\times 4.18\times (T_2-25)=393500  

T₂ = 43.46 °C  

6 0
3 years ago
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