The answer:
the main rules of the use of logarithm are
loga[a] = 1
loga[AxB] =loga[A] +loga[B] for all value positive of A and B
loga[A/B] = loga[A] - loga[B] for all value positive of A and B
in our case, <span>log8 4a (b-4/c4)
so it is equivalent to </span>log8 4a + <span>log8(b-4/c4)
and since </span>loga[A/B] = loga[A] l - oga[B] , log8(b-4/c4) =log8(b-4) - log8(c4)
the possible expression:
log8 4a (b-4/c4) = log8 4a + log8(b-4) - log8(c4)
aww,thank you ^^
i hope you're having a good day as well
Completely raw guess here but idk 3/5 cause you said two is decreased from both
Answer: (r-1)(r^2+r+1)(2r^3+13)
