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lapo4ka [179]
3 years ago
13

10 10 5 -10 0 10 -10 0 10 10 1.5 10 10 -10

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

???????................ .mm

vova2212 [387]3 years ago
3 0

Answer:

???????................ .mm

Step-by-step explanation:

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Which equation represents the standard form of f(x)?
blondinia [14]

Step-by-step explanation:

step 1. the standard form of a quadratic equation is f(x) = ax^2 + bx + c

step 2. since they are all in standard form you need to provide more information.

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An individual head of a sprinkler system covers a circular area of grass with a radius of 25 feet. the yard has 3 sprinkler head
frutty [35]

Answer:

Option D. 5890.5 feet²

Step-by-step explanation:

An individual head of a sprinkler system covers a circular are of grass with a radius of 25 feet.

Yard has three sprinkler heads that each cover circular area with no overlap.

We have to calculate the approximate area watered by these 3 sprinkler heads.

Area covered by one sprinkler = π×r² = π×(25)² = 625π feet²

Therefore area covered by three sprinkler heads = 3 × 625π = 5892.85 feet²

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3 0
3 years ago
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Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

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From definition we have:

$x=\log_{10}y

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