<span>You are given the following data and in order to answer the questions below, base your analysis in the given data.
Team Low High Range Mean Median IQR σ
Team A 22 58 36 42.1 44 18.25 10.35
Team B 38 49 11 43.9 44.5 3.5 2.97
Team C 27 36 9 31.8 32 3.75 2.55
Part A: If the club wants to award the team that has the most consistent scoring among its team members, the team that should it choose is Team B because it has only lesser points if it scored low, at 38 and it has the next to the highest score among the three team, which is 49. Also, the range of their performance is 43.9, a much better score than 42.1 in Team A and 31.8 in Team C.
Part B: If the club wants to award the team with the highest average score, </span>Team A because it has only lesser points if it scored low, at 22 and it has the highest score among the three team, which is 58.
P=2l+2w
120=2(2w)+(2w
120=4w+2w
120=6w
w=20
120=2(20)+2(l)
120=40+2l
80=2l
l=40
Length is 40 and width is 20 feet
hope this helps:)
Answer:
Step-by-step explanation:
As C and D are both at y = -9, the line below V₂ is vertical and located at
x = ½(22 + (-2) = 10
The line between V₁ and V₂ will contain the point halfway between B and D.
x = ½(14 + (-2)) = 6
y = ½(7 + (-9)) = -1
(6, -1)
The slope of the line between V₁ and V₂ is the same as between V₁ and our just found midpoint between B and D
m = (5 - (-1)) / (0 - 6) = -1
so the line equation is
y = -x + 5
Which intersects x = 10 at
y = -10 + 5 = -5
V₂ = (10, -5)
The distance between V₂ and B, C, and D is
d = √((14 - 10)² + (7 - (-5))²) = √160
The distance between V₁ and B, A, and D is
d = √((-10 - 0)² + (15 - 5)²) = √200
As √200 > √160, the dump should be located at V₁ or at least √200 away from any two of the points
The answer is A just add up all the correspond one
Y= -3/4x + b
2 = -3/4(8) + b
2 = -6 + b
add 6 to both sides and you get
8 = b
so Y=-3/4+8