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vladimir2022 [97]
3 years ago
6

Write the equation in slope intercept form when slope = 6/5 and the y- intercept =-8

Mathematics
1 answer:
Ratling [72]3 years ago
7 0

Step-by-step explanation:

Exercícios:

9. Sobre o estudo de equações, escreva V para as afirmações verdadeiras e F para as falsas.

a) ( ) A expressão 17 - 4x + 25 representa uma equação.

b) ( ) O número 23 representa um dos membros da equação -9x + 4 = 23.

c) ( ) Na equação x + 4 = 3x + 20, a incógnita é x.

d) ( ) A equação 3y - 15 = 0 não tem segundo membro.

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1. (5,8) m= 3<br> It wants me to write this in slope intercept form
ikadub [295]

Answer:

The answer is: y = 3x - 7

Step-by-step explanation:

Given point: (5, 8).

Slope m = 3

Use the point slope form and solve for y:

y - y1 = m(x - x1)

y - 8 = 3(x - 5)

y - 8 = 3x - 15

y = 3x - 15 + 8

y = 3x - 7

Proof:

f(x) = 3x - 7

f(5) = 3(5) - 7

= 15 - 7 = 8, giving (5, 8)

3 0
3 years ago
Read 2 more answers
A-1+a+a+a+a+3 into L cm
Sidana [21]

Answer:

sorry the question isn't obvious at all, can you please rectify?

3 0
2 years ago
I need help I have this problem and I think it either has to be simplified or turned into a fraction but I’m really sure it’s si
Olenka [21]
What are you specifially looking for? simplified it would be 10 and as a fraction 10 over 1
6 0
4 years ago
The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y
Lelechka [254]

Given the next quadratic function:

y=2x^2+3x-2

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

x_V=\frac{-b}{2a}

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:

6 0
1 year ago
PLZ HELP ASAP SOLID GEOMETRY WORD PROBLEMS
yan [13]
The volume of the candle initially is:
V=Ab*h
Area of the base of the cylinder: Ab=pi*r^2
pi=3.14
Radius of the base: r=4 cm
Height of the cylinder: h=6 cm

Ab=pi*r^2
Ab=3.14*(4 cm)^2
Ab=3.14*(16 cm^2)
Ab=50.24 cm^2

V=Ab*h
V=(50.24 cm^2)*(6 cm)
V=301.44 cm^3

The candle melts at a constant rate of:
r=(60 cm^3)/(2 hours)=(120 cm^3)/(4 hours)=(180 cm^3)/(6 hours)
r=30 cm^3/hour

The amount of candle melted off after 7 hours is:
A=(30 cm^3/hour)*(7 hours)
A=210 cm^3

The percent of candle that is melted off after 7 hours is:
P=(A/V)*100%
P=[(210 cm^3)/(301.44 cm^3)]*100%
P=(0.696656051)*100%
P=69.66560510%
Rounded to the nearest percent
P=70%

Answer: 70%

8 0
3 years ago
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