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kotykmax [81]
3 years ago
11

**Niaja’s cell phone company charges her $4.00 for every 48 text messages. How many text messages can Niaja send per dollar if s

he pays at a steady rate?
a) 112 texts per dollar

b) 12 texts per dollar

c) 44 texts per dollar

d) 448 texts per dollar

plzz show all workk !!
Mathematics
2 answers:
ollegr [7]3 years ago
6 0
The answer is B) 12 texts per dollar
kari74 [83]3 years ago
4 0
B) 12 texts per dollar

48/4 = 12
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Alekssandra [29.7K]
5\left( p+6 \right) =8p\\ \\ 5p+30=8p\\ \\ 8p-5p=30

\\ \\ 3p=30\\ \\ \frac { 1 }{ 3 } \cdot 3p=\frac { 1 }{ 3 } \cdot 30\\ \\ p=10
4 0
3 years ago
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Liz needs to keep no less than $500 in her checking account to avoid fees. She had $524.75 before writing a check for $65.99. Ho
geniusboy [140]

Answer: $41.24

Step-by-step explanation: In order to figure out how much she is away from 500 we need to first subtract the 65.99.

524.75 - 65.99 = 458.76

Then find the difference from 500 by subtracting again.

500 - 458.76 = 41.24

41.24 is the amount she needs to deposit in order to avoid a fee.

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3 years ago
Theo can run 1/2 mile in 1/10 hour. If theo continues at this rate how far can he run in a hour?
kirill [66]
1/2 mile x 10 = 5 miles
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3 years ago
Jason has 14 raspberry scones and 35 blackberry scones. He wants to make as many identical bags of scones as possible. Each bag
Natali5045456 [20]

Answer:

7 is the greatest number of bags Jason can fill.

Step-by-step explanation:

Given: Jason has 14 raspberry scones and 35 blackberry scones.

Now, finding the maximum number of bags Jason can fill with equal number of raspberry scones and blackberry scones.

∴ we will be using Greatest common factor (GCF) for knowing the number of bags.

14 = 2\times 7\\\\35= 5\times 7

∴ GCF= 7

7 is the greatest number of bags that Jason can fill with equal number of raspberry and blackberry scones.

           

5 0
3 years ago
Please help me with this i need help she is gonna call my mom again!!!​
telo118 [61]

Answer:

1. 15

2. -23

3. -16

Step-by-step explanation:

1. Find h(-8)

h(t) = \frac{5}{4}(4 - t)

h(-8) = \frac{5}{4}(4 -(-8))

h(-8) = \frac{5}{4}(4+8) =\frac{5}{4}(12)=5(3)=15

2. What is the value of g(-3)

g(x) = 4(x - 5) + x^{2}

g(-3) = 4(-3 - 5) -3^{2}

g(-3) = 4(-8) + 9

g(-3) = -32 + 9

g(-3) = -23

3. Find f(10)

f(x) = 14 - 3x

f(10) = 14 - 3(10)

f(10) = 14 - 30

f(10) = -16

7 0
3 years ago
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