All categories

1 year ago

The tank has 30,000 liters and 1,000 liters are taken out everyday. want was the amount of water in the tank 3 days ago

Mathematics

1 answer:

Dmitry [639]1 year ago

3 0

Answer:

33,000

Step-by-step explanation:

If 1000 liters are taken out every day that means 3000 liters were taken away 3days ago which means to find the old amount of water you add 3000 liters to 30,000 liters which makes 33,000 liters. Thanks plz mark branliest and like

You might be interested in

P=2L +2W;P=32,W=7 25 16 12.5 9

Marianna [84]

Answer:

L = 9

Step-by-step explanation:

Assuming you are trying to find L

P = 2L + 2W

P = 32

32 = 2L + 2W

W = 7

32 = 2L + (2 × 7)

32 = 2L + 14

2L = 32 - 14

2L = 18

L = 9

5 0

3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago

5/10 + 1/5 = ?? Simplify answer fully

Andreyy89

Multiply the second fraction by two; which gets you 5/10 + 2/10 = 7/10

6 0

2 years ago

A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an

liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

when the angle is 30 degrees

$tan(30) = \frac{6000}{d1}$

$d1 = \frac{6000}{tan(30)}$

$d1 = \frac{6000}{0.577}$

d1 = 10392.3 meters

when the angle is 60 degrees

$tan(60) = \frac{6000}{d2}$

$d2 = \frac{6000}{tan(60)}$

$d2 = \frac{6000}{1.732}\\$

d2 = 3464.1 meters

distance travelled by aircraft in 1 min is

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

Now converting to m/sec

=> $\frac{6928.2}{60}$

=>115.47 m/sec

4 0

3 years ago

What is the answer yall

kirza4 [7]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The tank has 30,000 liters and 1,000 liters are taken out everyday. want was the amount of water in the tank 3 days ago​

The tank has 30,000 liters and 1,000 liters are taken out everyday. want was the amount of water in the tank 3 days ago