Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Answer:
D. Open the compass so that the distance from the two points of the compass is wider than half the length of
.
Step-by-step explanation:
To construct a perpendicular for
, we must first take a compass & take the distance of its arms wider than half the length of
.
This is done in order to get two intersecting arcs in the top & bottom of
so that a perpendicular bisector can be drawn through it.
After two intersecting lines are drawn below & above
, draw a line joining these 2 points through their points of intersection. The point where it intersects
is the middle-most point of
& now a perpendicular bisector of
is constructed.

Step-by-step explanation:
you need too look somewhere else
Answer:
z/8
Step-by-step explanation:
cuz it says z and 8 in that order so z/8 please dont just ignore give me 5 star and thanks dont ignore if u do i will never help you
18,38,38,40,44,44,44,46,48....
the mean with the outlier (18) included is : 360/9 = 40
38,38,40,44,44,44,46,48
the mean with the outlier (18) excluded is : (360 - 18) / 9 = 342/9 = 38
so when the outlier is removed, the mean is 2 points less