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emmainna [20.7K]

2 years ago

13

Question 6(Multiple Choice Worth 3 points)

2 answers:

Shtirlitz [24]2 years ago

5 0

Answer:

a ≥ 9

Step-by-step explanation:

emmainna [20.7K]2 years ago

5 0

The answer is the last one

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Hello can you please help me posted picture of question

jarptica [38.1K]

4x^6+2x^5-2x+8+2x^8+4x+2=
2x^8+4x^6+2x^5+(4-2)x+10=
2x^8+4x^6+2x^5+2x+10

Answer: Option B: 2x^8+4x^6+2x^5+2x+10

7 0

3 years ago

1<br>Prove that<br>1: sin/1-cot + cos/1-tan=cos+sin

Anit [1.1K]

Answer:

have:

$\frac{sin}{1-cot}+\frac{cos}{1-tan}\\\\=\frac{sin}{1-\frac{cos}{sin} }+\frac{cos}{1-\frac{sin}{cos} }\\\\=\frac{sin^{2} }{sin-cos}+\frac{cos^{2} }{cos-sin} \\\\=\frac{sin^{2} }{sin-cos}-\frac{cos^{2} }{cos-sin}\\\\=\frac{sin^{2}-cos^{2} }{sin - cos}\\\\=\frac{(sin-cos)(sin+cos)}{sin-cos}\\\\=sin+cos$

Step-by-step explanation:

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2 years ago

Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

8090 [49]

Answer:

tanΘ = - $\frac{12}{5}$

Step-by-step explanation:

Using the trigonometric identities

• sin²x + cos²x = 1, hence

cosx = ± √(1 - sin²x )

• tanx = $\frac{sinx}{cosx}$

given sinΘ = $\frac{12}{13}$ , then

cosΘ = ± $\sqrt{1-(12/13)^2}$

Since Θ is in the second quadrant where cosΘ < 0, then

cosΘ = - $\sqrt{1-\frac{144}{169} }$

= - $\sqrt{\frac{25}{169} }$ = - $\frac{5}{13}$

tanΘ = $\frac{\frac{12}{13} }{\frac{-5}{13} }$

= $\frac{12}{13}$ × - $\frac{13}{5}$ = - $\frac{12}{5}$

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3 years ago

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Georgia [21]

The answer is 0.084.

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3 years ago

How many days are in a month

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It could be 30 to 31 but February has 28 expected from a leap year with 29 days

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2 years ago

Read 2 more answers