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Pachacha [2.7K]
3 years ago
6

Show all work to identify the asymptotes and zero of the function f(x)=6x/x^2-36

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

9514 1404 393

Answer:

  asymptotes: x = ±6

  zero: x = 0

Step-by-step explanation:

The vertical asymptotes of the function will be at the values of x where the denominator is zero. The denominator is x^2 -36, so has zeros for values of x that satisfy ...

  x^2 -36 = 0

  x^2 = 36

  x = ±√36 = ±6

The vertical asymptotes of the function are x = -6 and x = +6.

__

The zero of the function is at the value of x that makes the numerator zero. This will be the value of x that satisfies ...

  6x = 0

  x = 0 . . . . . divide by 6

The zero of the function is x=0.

__

As a check on this work, we have had a graphing calculator graph the function and identify the zero.

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Remark

All you need is 2 points to get the line of the equation. One is itself (B and B') is the same in both triangles. Now we need to find one more point. Since this is a reflection, the midpoint between C and C' is the second point. That choice of C and C' is completely arbitrary.

Step One

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Step Two

Find the midpoint between C and C'

C is (-4,-2) and C' is ( 0 , - 4) The midpoint is

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