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3 years ago

Show all work to identify the asymptotes and zero of the function f(x)=6x/x^2-36

Mathematics

1 answer:

makkiz [27]3 years ago

6 0

9514 1404 393

Answer:

asymptotes: x = ±6

zero: x = 0

Step-by-step explanation:

The vertical asymptotes of the function will be at the values of x where the denominator is zero. The denominator is x^2 -36, so has zeros for values of x that satisfy ...

x^2 -36 = 0

x^2 = 36

x = ±√36 = ±6

The vertical asymptotes of the function are x = -6 and x = +6.

The zero of the function is at the value of x that makes the numerator zero. This will be the value of x that satisfies ...

6x = 0

x = 0 . . . . . divide by 6

The zero of the function is x=0.

As a check on this work, we have had a graphing calculator graph the function and identify the zero.

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The quotient is 71 2/3 what is the divisor

Genrish500 [490]

The divisor is 3.
It is 3 because to make the whole number and the remainder a mixed number you take the whole number then for the numerator you write what is left over(remainder) and for the denominator you will write the divisor. In this case the denominator is 3 so the divisor is 3.

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4 0

3 years ago

How am i supposed to make a function? Number 15

Greeley [361]

Part A

<h3>Answer: T(n) = 58n+1800</h3>

-------------

Work Shown:

1800 = initial cost or starting cost

58*1 = 58 = cost for one person

58*2 = 116 = cost for two people

58*n = cost for n people

58n+1800 = total cost

58n+1800 = T(n)

T(n) = 58n+1800

======================================

Part B

<h3>Answer: D(T) = 0.85T</h3>

-------------

Work Shown:

T = total bill

15% discount means you still pay 85% of the bill (85%+15% = 100%)

D = discounted cost

D = 85% of T

D = 0.85*T

======================================

Part C

<h3>Answer: D(T(n)) = 49.3n + 1530</h3><h3>See attached image below for the table.</h3>

-------------

Work Shown:

We combine parts A and B.

T(n) = 58n+1800 from part A

D(T) = 0.85*T from part B

D(T(n)) = 0.85*( T(n) )

D(T(n)) = 0.85*( 58n+1800 ) ... plug in T(n) = 58n+1800

D(T(n)) = 0.85*( 58n+1800 )

D(T(n)) = 0.85*(58n)+0.85*(1800) ... distribute

D(T(n)) = 49.3n + 1530

If we plugged in n = 0, then,

D(T(n)) = 49.3n + 1530

D(T(0)) = 49.3*0 + 1530

D(T(0)) = 1530

Or we could plug n = 0 into T(n) to get T(0) = 1800

Then plug T = 1800 into D(T) = 0.85*T to get D(1800) = 1530

Either way you'll get the same answer.

Repeat this (using either method) for n = 50, 100, 150, 200 and you'll get the table of values you see below in the attached image.

======================================

Part D

The D( T(n) ) function allows us to find the discounted cost D for any number n of people that show up.

The input is n, where n is some positive integer less than or equal to 200 (because this is the reception hall's max capacity).

The output is the final discounted cost.

Example: n = 50 is one input which leads to its corresponding output of D( T(n) ) = 3995 as the table shows. So 50 people would have a discounted total cost of $3,995.