Show all work to identify the asymptotes and zero of the function f(x)=6x/x^2-36
1 answer:
9514 1404 393
Answer:
asymptotes: x = ±6
zero: x = 0
Step-by-step explanation:
The vertical asymptotes of the function will be at the values of x where the denominator is zero. The denominator is x^2 -36, so has zeros for values of x that satisfy ...
x^2 -36 = 0
x^2 = 36
x = ±√36 = ±6
The vertical asymptotes of the function are x = -6 and x = +6.
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The zero of the function is at the value of x that makes the numerator zero. This will be the value of x that satisfies ...
6x = 0
x = 0 . . . . . divide by 6
The zero of the function is x=0.
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As a check on this work, we have had a graphing calculator graph the function and identify the zero.
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Step-by-step explanation:
Given that average of 3 numbers is 85.
First two numbers are 81 and 86.
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3rd number so that average is 85
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Answer:
The decimal form of .
Step-by-step explanation:
We proceed to find the decimal form of , whose description is found below:
1) Multiplying the numerator by 100 and dividing it by 15:
Partial result: 0.06, Remainder: 10
2) Multiplying the remainder by the 10 and dividing it by 15:
Partial result: 0.066, Remainder: 10
3) Multiplying the remainder by the 10 and dividing it by 15:
Partial result: 0.0666, Remainder: 10
Since the decimal number is a infinite and periodical, we conclude that decimal form of .