Show all work to identify the asymptotes and zero of the function f(x)=6x/x^2-36
1 answer:
9514 1404 393
Answer:
asymptotes: x = ±6
zero: x = 0
Step-by-step explanation:
The vertical asymptotes of the function will be at the values of x where the denominator is zero. The denominator is x^2 -36, so has zeros for values of x that satisfy ...
x^2 -36 = 0
x^2 = 36
x = ±√36 = ±6
The vertical asymptotes of the function are x = -6 and x = +6.
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The zero of the function is at the value of x that makes the numerator zero. This will be the value of x that satisfies ...
6x = 0
x = 0 . . . . . divide by 6
The zero of the function is x=0.
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As a check on this work, we have had a graphing calculator graph the function and identify the zero.
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Answer:
The distance of the object from the base of cliff is 18.24 meters
Step-by-step explanation:
Given as :
The height of the vertical cliff = h = 50 meters
The distance of the object from the base of cliff = x meters
Let The angle of depression of object that level with cliff base = Ф = 70°
<u>Now, from figure</u>
Tan angle =
I.e TanФ =
Or, TanФ =
Or, Tan 70° =
Or, 2.74 =
∴ x =
I,e x = 18.24 meters
So, The distance of the object from the base of cliff = x = 18.24 meters
Hence,The distance of the object from the base of cliff is 18.24 meters Answer
