Show all work to identify the asymptotes and zero of the function f(x)=6x/x^2-36
1 answer:
9514 1404 393
Answer:
asymptotes: x = ±6
zero: x = 0
Step-by-step explanation:
The vertical asymptotes of the function will be at the values of x where the denominator is zero. The denominator is x^2 -36, so has zeros for values of x that satisfy ...
x^2 -36 = 0
x^2 = 36
x = ±√36 = ±6
The vertical asymptotes of the function are x = -6 and x = +6.
__
The zero of the function is at the value of x that makes the numerator zero. This will be the value of x that satisfies ...
6x = 0
x = 0 . . . . . divide by 6
The zero of the function is x=0.
__
As a check on this work, we have had a graphing calculator graph the function and identify the zero.
You might be interested in
the average rate of change is just the slope from (0,f(0)) to (1,f(1))
find f(0) and f(1)
slope from (0,3) to (1,3) is rise/run=(3-3)/(0-1)=0/-1
the average rate of change from x=0 to x=1 for f(x) is 0