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melamori03 [73]

3 years ago

10

A tree casts a shadow 60 feet long. At the same time, a nearby 8-foot post casts a 12- foot shadow. How tall is the tree?

1 answer:

Alborosie3 years ago

3 0

9514 1404 393

Answer:

40 ft

Step-by-step explanation:

The post is 8/12 = 2/3 as tall as the shadow is long. We expect the same relationship holds for the tree.

tree height = (2/3)(shadow length) = (2/3)(60 ft) = 40 ft

The tree is 40 feet tall.

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on the first play the football team loss 6 yards. on the second play the team lost 5 yards. what was their total?

Neporo4naja [7]

-11 or the Team lost 11 yards

8 0

3 years ago

Read 2 more answers

100 POINTS HELP ASAP Linear Combination

notka56 [123]

Answer:

1) $x=\dfrac12$

2) $n = -3 \ \ \textsf{and} \ \ m = -4$

3) see below

4) A: 0 = 1

Step-by-step explanation:

<u>Question 1</u>

$15-0.5(4x-2)+4x=17$

$\implies 15-2x+1+4x=17$

$\implies 2x+16=17$

$\implies 2x=1$

$\implies x=\dfrac12$

<u>Question 2</u>

$\textsf{rearrange} \ n=m+1 :$

$\implies -m=-n+1$

$\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\$

$\implies0=n+3$

$\implies n=-3$

$\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:$

$\implies m=-3-1$

$\implies m=-4$

<u>Question 3</u>

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

<u>Question 4</u>

$3j=k$

$k=3j+1$

$\textsf{rearrange} \ 3j=k :$

$\implies -k=-3j$

$\textsf{add equations}\ -k=-3j \ \ \textsf{and}\ \ k=3j+1:$

$\implies 0=1$

Solution = A

6 0

3 years ago

Sandy paid $20.30 as the sales tax for a bike she bought. If the sales tax is

BigorU [14]

Answer:

21.72

Step-by-step explanation:

0.07 x 20.30

4 0

3 years ago

Find the lengths of the sides of the triangle PQR. P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) a. |PQ| = b. |QR| = c. |RP| =

Nat2105 [25]

Given :

Three points , P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) .

To Find :

The length of sides .

Given :

We know , length of two points P(x,y ,z) and Q(a,b,c) is given by :

$L=\sqrt{(x-a)^2+(y-b)^2+(z-c)^2}$

Length of PQ :

$PQ=\sqrt{(4-2)^2+(3-1)^2+(4-3)^2}\\\\PQ=\sqrt{4+4+1}=\sqrt{9}\\\\PQ=3$

Length of QR :

$QR=\sqrt{(2-2)^2+(1-7)^2+(3-0)^2}\\\\QR=\sqrt{0+6^2+3^2}\\\\QR=\sqrt{36+9}\\\\QR=\sqrt{45}\\\\QR=3\sqrt{5}$ :

Length of RP :

$RP=\sqrt{(2-4)^2+(7-3)^2+(0-4)^2}\\\\RP=\sqrt{2^2+4^2+4^2}\\\\RP=\sqrt{4+16+16}\\\\RP=\sqrt{36}\\\\RP=6$

Hence , this is the required solution .

4 0

3 years ago

Solve 2x2 + 4x = 6 by factoring.

Reil [10]

Answer:

all work is shown and pictured

5 0

4 years ago