Simplify 6a^2 - 2c + 2a^2 + 2c^2
2 answers:
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The total is $39 u can look at the pic to see how it was solve
Hey there!
To find percent error, we find the difference between the prediction and the actual value. We take that difference, divide it by the prediction, and multiply it by 100.
So let's find the difference.
42 - 30 = 12
Divide the difference, which is 12, by 30.
12 ÷ 30 = 0.4
Multiply this by 100 to get the percent.
0.4 x 100 = 40
The percent error is 40%.
Hope this helps!
Answer:
The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.
Step-by-step explanation:
The complete question is:
The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.
Solution:
The (1 - <em>α</em>)% confidence interval for population mean is:
The margin of error for this interval is:
The critical value of <em>z</em> for 90% confidence level is:
<em>z</em> = 1.645
Compute the required sample size as follows:
Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.